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almond37 [142]
3 years ago
15

If 1.0 gram of hydrogen reacts with 19.0 grams of fluorine, then what is the percent by mass of fluorine in the compound that is

formed?
Chemistry
2 answers:
astraxan [27]3 years ago
8 0
The reaction between hydrogen (H2) and fluorine (F2) is given below,
                                   H2 + F2 ---> 2HF
One mole of both hydrogen and fluorine yields to 2 moles of hydrogen fluoride. This can also be expressed as, 2 grams of hydrogen and 38 grams of fluorine will form 40 grams of hydrogen fluoride. From the given, only 20 grams of HF is formed with 19 g of it being fluorine. Thus, the percentage fluorine of the compound formed is 95%. 
Vinil7 [7]3 years ago
3 0

Answer : The mass percent of fluorine in the compound is, 95%

Explanation :

Mass percent : It is defined as the mass of the given component present in the total mass of the compound.

Formula used :

\text{Mass} \%\text{ F}=\frac{\text{Mass of F}}{\text{Mass of }H+\text{Mass of }F}\times 100

Now put all the given values in this formula, we get the mass percent of fluorine in the compound.

\text{Mass} \%\text{ F}=\frac{19g}{1g+19g}\times 100=95\%

Therefore, the mass percent of fluorine in the compound is, 95%

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A chemistry graduate student is given 500. mL of a 0.20 M chloroacetic acid (HCH2ClCO2) solution. Chloroacetic acid is a weak ac
zhenek [66]

Answer:

12 g of choloracetic acid

Explanation:

The buffer equilibrium is:

HCH₂ClCO₂ ⇄ CH₂ClCO₂⁻ + H⁺

pka= -log ka =

Ka: 1,3x10⁻³ = [CH₂ClCO₂⁻] [H⁺] / [HCH₂ClCO₂]

By Henderson-Hasselbalch equation:

pH = pka + log₁₀ [A⁻] / [HA]

3,01 = 2,89 + log₁₀ [A⁻] / [HA]

1,318 = [A⁻] / [HA]

As molar concentration of chloroacetic acid (HA) is 0,20M

[A⁻] = 0,26 mol/L

The volume is 500 mL ≡ 0,5 L

0,26mol/L × 0,5 L = 0,13 moles of chloroacetic acid. In grams:

0,13 mol × (94,5g / 1mol) = <em>12 g of choloracetic acid</em>

<em></em>

I hope it helps!

3 0
3 years ago
Describe how you could prove that a bicycle is matter
Ainat [17]

Answer:

Explanation:

Matter is anything that has weight and occupies space.

To prove that a bicycle is a matter, we need to show that it has weight and will occupy space.

When you put the bicycle on a weighing scale, you will see the weight of the bicycle. This a proof that bicycle is a matter.

To show that the bicycle can occupy space, place the device in a tank full of water. From the tank, the bicycle will displace some water. Substances that cannot occupy space will not behave in such manner.

5 0
3 years ago
How will you separate a solution of benzene and chloroform?
Troyanec [42]

Answer:

\huge\boxed{\sf Distillation}

Explanation:

  • State of benzene at RTP = liquid
  • State of chloroform at RTP = liquid
  • Boiling point of benzene = 80.1 °C
  • Boiling point of chloroform = 61.2 °C

Since, both of the chemicals are liquids, we can separate it by the process of distillation.

<u>Distillation:</u>

  • is the process in which we separate two liquids on the basis of their difference in boiling points.

<u>How it works:</u>

Since chloroform has less boiling point, it will evaporate and collected first and benzene will follow it after sometime.

- Apparatus of distillation is in the attached file.

\rule[225]{225}{2}

7 0
2 years ago
Zinc metal and aqueous silver nitrate react to give Zn(NO3)2(aq) plus silver metal. When 5.00 g of Zn(s) and solution containing
Fittoniya [83]

Answer : The percent yield is, 83.51 %

Solution : Given,

Mass of Zn = 5.00 g

Mass of AgNO_3 = 25.00 g

Molar mass of Zn = 65.38 g/mole

Molar mass of AgNO_3 = 168.97 g/mole

Molar mass of Ag = 107.87 g/mole

First we have to calculate the moles of Zn and AgNO_3.

\text{ Moles of }Zn=\frac{\text{ Mass of }Zn}{\text{ Molar mass of }Zn}=\frac{5.00g}{65.38g/mole}=0.0765moles

\text{ Moles of }AgNO_3=\frac{\text{ Mass of }AgNO_3}{\text{ Molar mass of }AgNO_3}=\frac{25.00g}{168.97g/mole}=0.1479moles

Now we have to calculate the limiting and excess reagent.

The balanced chemical reaction is,

Zn+2AgNO_3\rightarrow Zn(NO_3)_2+2Ag

From the balanced reaction we conclude that

As, 2 mole of AgNO_3 react with 1 mole of Zn

So, 0.1479 moles of AgNO_3 react with \frac{0.1479}{2}=0.07395 moles of Zn

From this we conclude that, Zn is an excess reagent because the given moles are greater than the required moles and AgNO_3 is a limiting reagent and it limits the formation of product.

Now we have to calculate the moles of Ag

From the reaction, we conclude that

As, 2 mole of AgNO_3 react to give 2 mole of Ag

So, 0.1479 moles of AgNO_3 react to give 0.1479 moles of Ag

Now we have to calculate the mass of Ag

\text{ Mass of }Ag=\text{ Moles of }Ag\times \text{ Molar mass of }Ag

\text{ Mass of }Ag=(0.1479moles)\times (107.87g/mole)=15.95g

Theoretical yield of Ag = 15.95 g

Experimental yield of Ag = 13.32 g

Now we have to calculate the percent yield.

\% \text{ yield}=\frac{\text{ Experimental yield of }Ag}{\text{ Theretical yield of }Ag}\times 100

\% \text{ yield}=\frac{13.32g}{15.95g}\times 100=83.51\%

Therefore, the percent yield is, 83.51 %

7 0
3 years ago
Why is molybdenum a good conductor of electricity
SCORPION-xisa [38]

Answer: Because it is has a strong connection

Explanation:

7 0
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