The moles of ammonia in 1.20 x10^25 molecules of ammonia is calculated as follows
by use of Avogadro constant
1moles = 6.02 x10^23
what about 1.20 x10^25 moles
by use of cross multiplication
= 1 mole x ( 1.20 x10^25) /( 6.02 x10^23) = 19.93 moles
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False I hope this is right
That is True XD
Hope that helps :D
1AlBr3+ 3K ---> 3KBr + 1Al
