We need to dilute 0.400 mol of copper (II) sulfate, how do we know, how many weigh of

we have to dilute??
It's simple.

Using a periodic table we can find the molar mass of


Then

now we can replace it


Then we have to dilute 63.84 grams of copper (II) sulfate in 1 L of water to obtain a solution with 0.400M
Answer:
235k
Explanation:
To solve this problem, we will use the general gas equation.
In its simplest form, the general gas equation can be represented as follows:
P1V1/T1 = P2V2/T2
P1 = 700mmHg
V1 = 760ml
T1 = 40 degrees Celsius = 40 + 273.15 = 313.15K ( conversion into standard temperature unit)
P2 = 1.25 atm
We have to covert this into the same unit as the first pressure.
760mmHg = 1atm
x mmHg = 1.25 atm
x = 1.25 * 760 = 950mmHg
V2 = 420ml
T2 = ?
Now, rearranging the equation will yield:
T2 = P2V2T1/P1V1
T2 = 950 * 420 * 313.5/700 * 760
T2 = 235.125K or -38.025 degrees celcius