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3 years ago

True or False:

Chemistry

1 answer:

nordsb [41]3 years ago

6 0

Is 2502 and 2503 supposed to be 2SO2 and 2SO3??
I’m pretty sure it’s true as the in front of the SO3 is 2

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A 2.0 mL sample of air in a syringe exerts a pressure of 1.02 atm at 22 C. If that syringe is placed into boiling water at 100 C

emmainna [20.7K]

Answer: The new volume of the air in the syringe is 7.3 mL.

Explanation:

Given: $V_{1}$ = 2.0 mL, $P_{1}$ = 1.02 atm, $T_{1} = 22^{o}C$

$V_{2}$ = ?, $P_{2}$ = 1.27 atm, $T_{2} = 100^{o}C$

Formula used to calculate the new volume in syringe is as follows.

$\frac{P_{1}V_{1}}{T_{1}} = \frac{P_{2}V_{2}}{T_{2}}$

Substitute the values into above formula as follows.

$\frac{P_{1}V_{1}}{T_{1}} = \frac{P_{2}V_{2}}{T_{2}}\\\frac{1.02 atm \times 2.0 mL}{22^{o}C} = \frac{1.27 atm \times V_{1}}{100^{o}C}\\V_{1} = 7.3 mL$

Thus, we can conclude that the new volume of the air in the syringe is 7.3 mL.

6 0

3 years ago

All rocks began as what type of rock?<br> planetary<br> igneous<br> metamorphic<br> sedimentary

zlopas [31]

Answer:

Igneous

Explanation:

3 0

3 years ago

The titration of 25.00 ml a 0.125 m hclo4 solution requires 27.07 ml of koh to reach the endpoint. what is the concentration of

agasfer [191]

Answer : The concentration of the $KOH$ is, 0.115 M

Explanation :

Using dilution law,

$n_1M_1V_1=n_2M_2V_2$

where,

$n_1$ = basicity of an acid = 1

$n_2$ = acidity of a base = 1

$M_1$ = concentration of $HClO_4$ = 0.125 M

$M_2$ = concentration of KOH = ?

$V_1$ = volume of $HClO_4$ = 25 ml

$V_2$ = volume of NaOH = 27.07 ml

Now put all the given values in the above law, we get the concentration of the $KOH$ .

$1\times 0.125M\times 25ml=1\times M_2\times 27.07ml$

$M_2=0.115M$

Therefore, the concentration of the $KOH$ is, 0.115 M

5 0

4 years ago

The total number of each element is not changed during a chemical reaction

Paha777 [63]

false all element when they are combined eachother thier valance number will change

the combination of oxygen and aluminum gives us Al2O3 see even the numbers are changing thank you if you have a comment you can write

3 0

4 years ago

A multistep reaction can only occur as fast as its slowest step. Therefore, it is the rate law of the slow step that determines

kodGreya [7K]

Answer : The rate law for the overall reaction is, $Rate=k[A][B]$

Explanation :

Rate law : It is defined as the expression which expresses the rate of the reaction in terms of molar concentration of the reactants with each term raised to the power their stoichiometric coefficient of that reactant in the balanced chemical equation.

As we are given the mechanism for the reaction :

Step 1 : $A+B\rightarrow AB$ (slow)

Step 2 : $A+AB\rightarrow A_2B$ (fast)

Overall reaction : $2A+B\rightarrow A_2B$

The rate law expression for overall reaction should be in terms of A and B.

As we know that the slow step is the rate determining step. So,

The slow step reaction is,

$A+B\rightarrow AB$

The expression of rate law for this reaction will be,

$Rate=k[A][B]$

Hence, the rate law for the overall reaction is $Rate=k[A][B]$

3 0

3 years ago