Answer:
The answer to your question is letter A
Explanation:
Data
Mass ratio 1.62 to 1.00
Atomic mass Cr = 52 g
Atomic mass O = 16
Process
1.- Calculate the proportion Chromium to Oxygen to each possible solutions
a) CrO₃ = ![\frac{52}{16 x 3} = \frac{52}{48} = 1.08](https://tex.z-dn.net/?f=%5Cfrac%7B52%7D%7B16%20x%203%7D%20%3D%20%5Cfrac%7B52%7D%7B48%7D%20%3D%201.08)
b) CrO₂ = ![\frac{52}{16 x 2} = \frac{52}{32} = 1.63](https://tex.z-dn.net/?f=%5Cfrac%7B52%7D%7B16%20x%202%7D%20%3D%20%5Cfrac%7B52%7D%7B32%7D%20%3D%201.63)
c) CrO = ![\frac{52}{16} = 3.25](https://tex.z-dn.net/?f=%5Cfrac%7B52%7D%7B16%7D%20%3D%203.25)
d) Cr₂O =
Answer:
The concentrations are :
![[HAsc^-]=0.000702 M](https://tex.z-dn.net/?f=%5BHAsc%5E-%5D%3D0.000702%20M)
![[Asc^{2-}]=5.92\times 10^{-8} M](https://tex.z-dn.net/?f=%5BAsc%5E%7B2-%7D%5D%3D5.92%5Ctimes%2010%5E%7B-8%7D%20M)
The pH of the solution is 3.15.
Explanation:
![K_{a1}=1.0\times 10^{-5}](https://tex.z-dn.net/?f=K_%7Ba1%7D%3D1.0%5Ctimes%2010%5E%7B-5%7D)
Initial
c 0 0
Equilibrium
c-x x x
![K_{a1}=\frac{[HAs^-][H^+]}{[H_2Asc]}](https://tex.z-dn.net/?f=K_%7Ba1%7D%3D%5Cfrac%7B%5BHAs%5E-%5D%5BH%5E%2B%5D%7D%7B%5BH_2Asc%5D%7D)
![1.0\times 10^{-5}=\frac{x\times x}{(c-x)}](https://tex.z-dn.net/?f=1.0%5Ctimes%2010%5E%7B-5%7D%3D%5Cfrac%7Bx%5Ctimes%20x%7D%7B%28c-x%29%7D)
![1.0\times 10^{-5}=\frac{x^2}{(0.050-x)}](https://tex.z-dn.net/?f=1.0%5Ctimes%2010%5E%7B-5%7D%3D%5Cfrac%7Bx%5E2%7D%7B%280.050-x%29%7D)
Solving for x:
x = 0.000702 M
![[HAsc^-]=0.000702 M](https://tex.z-dn.net/?f=%5BHAsc%5E-%5D%3D0.000702%20M)
![K_{a2}=5\times 10^{-12}](https://tex.z-dn.net/?f=K_%7Ba2%7D%3D5%5Ctimes%2010%5E%7B-12%7D)
Initially
x 0 0
At equilibrium ;
(x - y) y y
![K_{a2}=\frac{[As^{2-}][H^+]}{[HAsc^-]}](https://tex.z-dn.net/?f=K_%7Ba2%7D%3D%5Cfrac%7B%5BAs%5E%7B2-%7D%5D%5BH%5E%2B%5D%7D%7B%5BHAsc%5E-%5D%7D)
![5\times 10^{-12}=\frac{y\times y}{(x-y)}](https://tex.z-dn.net/?f=5%5Ctimes%2010%5E%7B-12%7D%3D%5Cfrac%7By%5Ctimes%20y%7D%7B%28x-y%29%7D)
![5\times 10^{-12}=\frac{y^2}{(x-y)}](https://tex.z-dn.net/?f=5%5Ctimes%2010%5E%7B-12%7D%3D%5Cfrac%7By%5E2%7D%7B%28x-y%29%7D)
Putting value of x = 0.000702 M
![5\times 10^{-12}=\frac{y^2}{(0.000702 -y)}](https://tex.z-dn.net/?f=5%5Ctimes%2010%5E%7B-12%7D%3D%5Cfrac%7By%5E2%7D%7B%280.000702%20-y%29%7D)
![y=5.92\times 10^{-8} M](https://tex.z-dn.net/?f=y%3D5.92%5Ctimes%2010%5E%7B-8%7D%20M)
![[Asc^{2-}]=5.92\times 10^{-8} M](https://tex.z-dn.net/?f=%5BAsc%5E%7B2-%7D%5D%3D5.92%5Ctimes%2010%5E%7B-8%7D%20M)
Total concentration of ![[H^+]=x+y=0.000702 M+5.92\times 10^{-8} M=7.0206\times 10^{-4} M](https://tex.z-dn.net/?f=%5BH%5E%2B%5D%3Dx%2By%3D0.000702%20M%2B5.92%5Ctimes%2010%5E%7B-8%7D%20M%3D7.0206%5Ctimes%2010%5E%7B-4%7D%20M)
The pH of the solution :
![pH=-\log[H^+]](https://tex.z-dn.net/?f=pH%3D-%5Clog%5BH%5E%2B%5D)
![pH=-\log[7.0206\times 10^{-4} M}=3.15](https://tex.z-dn.net/?f=pH%3D-%5Clog%5B7.0206%5Ctimes%2010%5E%7B-4%7D%20M%7D%3D3.15)
Answer: a heterogenous mixture is simply any mixture that is not uniform in composition- its non-uniform mixture of smaller constituent parts
Explanation:
A chemical change
Explanation:
In this reaction, a chemical change has occurred, here are some indicators of chemical changes from the reaction;
Chemical changes are changes in which new products are formed.
- Formation of bubbles and precipitates: these are new substances that indicates a chemical change. The bubbles and insoluble precipitate are good indicators of chemical change.
- A temperature change that is large; This is also typifies chemical changes. When temperature rises in reaction, a chemical change has occurred.
- The bubbles and precipitates cannot be combined to give the reactants. The reaction is irreversible.
learn more:
Chemical change brainly.com/question/9388643
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