Answer: Option (d) is the correct answer.
Explanation:
An oxidizing agent is defined as the substance that itself gains an electron and helps in oxidation of another substance.
For example, ![Ag^{+} + 1e^{-} \rightarrow Ag](https://tex.z-dn.net/?f=Ag%5E%7B%2B%7D%20%2B%201e%5E%7B-%7D%20%5Crightarrow%20Ag)
Here,
is the oxidizing agent.
Also, a substance with more positive value of electrode potential will be the strongest oxidizing agent. Whereas a substance with more negative value of electrode potential will be the strongest reducing agent.
Therefore, out of the given options
has the highest positive value of electrode potential so,
is the strongest oxidizing agent.
The name for the ionic compound Cs2S is Cesium sulfide.
Answer:
Amount of sucrose required = 278.85 g
Explanation:
(w/v)% = 39.0 %
Volume of the solution = 715 mL
39% (w/v) means 39 g of sucrose present in 100 mL of the solution.
Using unitary method,
For making 39% solution,
100 mL solution requires 39 g of the sucrose
therefore, 715 mL solution requires:
![715\;mL \times\frac{39\;g}{100\;mL}](https://tex.z-dn.net/?f=715%5C%3BmL%20%5Ctimes%5Cfrac%7B39%5C%3Bg%7D%7B100%5C%3BmL%7D)
= 278.85 g
Answer:
Explanation:
Using integrated rate law for first order kinetics as:
Where,
is the concentration at time t
is the initial concentration
Given:
75 % is decomposed which means that 0.75 of
is decomposed. So,
= 1 - 0.75 = 0.25
t = 60 min
k = 0.023 min⁻¹
Considering the expression for half life as:-
Where, k is rate constant
So,