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Charra [1.4K]
2 years ago
12

A Smart Car, which has a mass of 1000 kg, is going 20 m/s. When it hits the barrier, it stops with a time of 0.5 seconds. What i

s the change in momentum of the car?
Physics
1 answer:
antiseptic1488 [7]2 years ago
4 0

Answer:

The change in momentum = -20000 kg m/s.

Explanation:

Mass m = 1000 kg

speed v₁ = 20 m/s

speed v₂ = 0 m/s

We know that,

The change in momentum

ΔP = m (Δv)

ΔP = m (v₂ - v₁)

     = 1000 (0 - 20)

     = 1000 (-20)

     = -20000 kg m/s

Thus, the change in momentum = -20000 kg m/s.

Note: negative sign indicates that the velocity is reducing when it hits the barrier.

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A plane travels 350 km south along a straight path with an average velocity of 125 km/h to the south. The plane has a 30 minute
faust18 [17]
Average Velocity = Total Displacement / Total time

1st part of journey,  350 km at velocity 125 km/h

Time = 350 / 125 = 2.8 hours.

2nd part of journey,  220 km at velocity 115 km/h

Time = 220 / 115 = 1.9 hours


Average Velocity = Total Displacement / Total time

                               = (350 + 220) / (2.8 + 1.9)

                                =   570 / 4.7  ≈ 121.3 km/hr

Average Velocity ≈ 121 km/hr due south. 

Option C. 
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3 years ago
Test questions!!!!!!!!
Pani-rosa [81]

Answer:

B. surface wave

8 0
2 years ago
What is the acceleration of a Porsche that can go from 15 mi/hr to 75 mi/hr in 4 seconds?
Elodia [21]

Hi there!

Acceleration = change in velocity / change in time = Δv/Δt

Thus:

a = (75 - 15)/4 = 60/4 = 15 mi/hr²

8 0
2 years ago
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A solid metal object hangs from a force sensor by a thread in the open air, and the actual weight is measured to be 0.71 N. Then
Alexeev081 [22]

Answer:

The apparent weight of the object is 0.465 N.

Explanation:

Given that,

Weight = 0.71 N

Water level = 50 mL

object inserted = 75 mL

We need to calculate the volume of solid

Using formula of volume

V=25\ ml = 25\times10^{-6}\ m^3

We need to calculate the buoyancy force

Using formula of buoyancy force

F'= V\rho g

Put the value into the formula

F'=25\times10^{-6}\times1000\times9.8

F'=0.245\ N

We need to calculate the apparent weight of the object

Using formula of apparent weight

W=F-F'

Put the value into the formula

W=0.71-0.245

W=0.465\ N

Hence, The apparent weight of the object is 0.465 N.

5 0
2 years ago
during a typical afternoon thunderstorm in the summer, an area of 66.0 km2 receives 9.57 108 gal of rain in 18 min. how many inc
zheka24 [161]

Answer:

2.16 inch

Explanation:

area under water = 66 km²

= 66 x ( 3280.84 x 12 )² inch²

= 1.023 x 10¹¹ sq inch

volume of rain = 9.57 x 10⁸  gallon = 9.57 x 10⁸ x 231 inch³

= 2.21 x 10¹¹ inch³

If depth of rainfall be t

volume of rain = surface area x depth

= 1.023 x 10¹¹ x t

So ,

1.023 x 10¹¹ x t  = 2.21 x 10¹¹

t = 2.16 inch

5 0
2 years ago
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