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3 years ago

A model of a skyscraper uses the scale of 2 inches = 45 feet. If the actual skyscraper is 992 feet tall, how tall is the model?

Mathematics

1 answer:

kvasek [131]3 years ago

8 0

Answer:

44.08 or 44.1

Step-by-step explanation:

OK so the basics of this question is that for every 45 feet of the actual skyscraper we have 2 inches in the model. The first thing we do is divide 992/45 which equals 22.04. Know if this was 1 inch for every 45 feet we would be done however we need to multiply this number by 2 to get our answer so 22.04*2 =44.08

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Answer:

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uysha [10]

Answer:

$\frac{x^{2}}{36} - \frac{y^{2}}{64}=1$

Step-by-step explanation:

Given an hyperbola with the following conditions:

Foci at (-10,0) and (10,0)
x-intercept +/- 6;

The following holds:

The center is midway between the foci, so the center must be at (h, k) = (0, 0).

The foci are 10 units to either side of the center, so c = 10 and $c^2 = 100$
The center lies on the origin, so the two x-intercepts must then also be the hyperbola's vertices.

Since the intercepts are 6 units to either side of the center, then a = 6 and $a^2 = 36.$

$Then, a^2+b^2=c^2\\b^2=100-36=64$

Therefore, substituting $a^2 = 36.$ and $b^2=64$ into the standard form

$\frac{x^{2}}{a^2} - \frac{y^{2}}{b^2}=1\\We \: have:\\ \dfrac{x^{2}}{36} - \dfrac{y^{2}}{64}=1$

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