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3 years ago

A model of a skyscraper uses the scale of 2 inches = 45 feet. If the actual skyscraper is 992 feet tall, how tall is the model?

Mathematics

1 answer:

kvasek [131]3 years ago

8 0

Answer:

44.08 or 44.1

Step-by-step explanation:

OK so the basics of this question is that for every 45 feet of the actual skyscraper we have 2 inches in the model. The first thing we do is divide 992/45 which equals 22.04. Know if this was 1 inch for every 45 feet we would be done however we need to multiply this number by 2 to get our answer so 22.04*2 =44.08

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Find the stated lengths in each parallelogram

alexandr1967 [171]

Answer:

40/3, 172/3, respectively

Step-by-step explanation:

x + 9 = 2y

2x = 2y + 2

x + 9 = 2(2x - 2)

4x - 4 = x + 9

3x - 13 = 0

x = 13/3

y = 40/6

RT = 13/3 + 9 = 40/3

QS = 160/3 + 4 = 172/3

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3 years ago

PLEASE HELP..................James is paid $18 an hour at his new job. He wishes to graph his total pay T, as a function of the

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450 AND 50.................

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3 years ago

Read 2 more answers

Can you solve it ????

Dima020 [189]

Angle ABD=87 degrees
angle ABC+angle CBD= angle ABD
Therefore, 9x-1+6x+58=87
15x+57=87
15x=87-57
15x=30
x=30/15
x=2

Angle ABC= 9x-1
=9(2)-1
=18-1
=17 degrees

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3 years ago

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3 years ago

A realtor would like to create a 95% confidence interval for the average price of a house in Franklin County, Ohio. To accomplis

VMariaS [17]

Answer:

$320128-1.96\frac{50324}{\sqrt{529}}=315839.52$

$320128+1.96\frac{50324}{\sqrt{529}}=324416.48$

So on this case the 95% confidence interval would be given by (315839.52;324416.48)

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X=320128$ represent the sample mean

$\mu$ population mean (variable of interest)

$\sigma=50324$ represent the population standard deviation

n=529 represent the sample size

Solution to the problem

The confidence interval for the mean is given by the following formula:

$\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$ (1)

Since the Confidence is 0.95 or 95%, the value of $\alpha=0.05$ and $\alpha/2 =0.025$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-NORM.INV(0.025,0,1)".And we see that $z_{\alpha/2}=1.96$

Now we have everything in order to replace into formula (1):

$320128-1.96\frac{50324}{\sqrt{529}}=315839.52$

$320128+1.96\frac{50324}{\sqrt{529}}=324416.48$

So on this case the 95% confidence interval would be given by (315839.52;324416.48)

8 0

3 years ago