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Tems11 [23]
3 years ago
12

A model of a skyscraper uses the scale of 2 inches = 45 feet. If the actual skyscraper is 992 feet tall, how tall is the model?

Mathematics
1 answer:
kvasek [131]3 years ago
8 0

Answer:

44.08 or 44.1

Step-by-step explanation:

OK so the basics of this question is that for every 45 feet of the actual skyscraper we have 2 inches in the model. The first thing we do is divide 992/45 which equals 22.04. Know if this was 1 inch for every 45 feet we would be done however we need to multiply this number by 2 to get our answer so 22.04*2 =44.08

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Answer:

<DEB= 125 degrees

Step-by-step explanation:

To get this, you would need to know all 2 angles of the triangle.

To find the first angle, simply do 180-107 to get 73(because supplementary angles add up to 180 degrees).

Next, 180-52(given angle)-73 to get 55 because the 3 angles of a triangle add up to 180(triangle angle sum theory).

You would see that <DEB is part of another supplementary angle so, do 180-55 to get 125.

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Find the standard form of the equation of the hyperbola satisfying the given conditions: X intercept +/- 6; foci at (-10,0) and
uysha [10]

Answer:

\frac{x^{2}}{36} - \frac{y^{2}}{64}=1

Step-by-step explanation:

Given an hyperbola with the following conditions:

  • Foci at (-10,0) and (10,0)
  • x-intercept +/- 6;

The following holds:

  • The center is midway between the foci, so the center must be at (h, k) = (0, 0).
  • The foci are 10 units to either side of the center, so c = 10 and c^2 = 100
  • The center lies on the origin, so the two x-intercepts must then also be the hyperbola's vertices.

Since the intercepts are 6 units to either side of the center, then a = 6 and a^2 = 36.

Then, a^2+b^2=c^2\\b^2=100-36=64

Therefore, substituting a^2 = 36. and b^2=64 into the standard form

\frac{x^{2}}{a^2} - \frac{y^{2}}{b^2}=1\\We \: have:\\ \dfrac{x^{2}}{36} - \dfrac{y^{2}}{64}=1

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