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lara [203]
3 years ago
7

Please answer ASAP I really need it is it the 1st,2nd,3rd, or 4th Anwser

Chemistry
1 answer:
umka21 [38]3 years ago
4 0

Answer:

3rd

Explanation:

i just took the test

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My brain hurts...<br><br> SOMEONE PLEASE EXPLAIN THIS
Slav-nsk [51]

Answer:

IT MAKES NO SENSE LOL Explanation:

5 0
3 years ago
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Explain with equations and calculations, when necessary, whether an aqueous solution of each of these salts is acidic, basic, or
Lelechka [254]

(CH₃)₂NH₂Br is an acidic salt.

<h3>What are acidic salts?</h3>

Neutralization of a strong acid with a weak base gives an acidic salt.

Examples: Ammonium chloride, Copper sulfate, Silver nitrate

<h3>What are basic salts?</h3>

Neutralization of a weak acid with a strong base gives a basic salt.

Examples: Sodium Acetate, Potassium cyanide, Sodium sulfide

<h3>What are neutral salts?</h3>

They are formed by the neutralization of strong acids and strong bases, are called neutral salts because their aqueous solutions are neutral to litmus.  

Examples: The compounds like NaCl, KCl, K2S04, NaN03, KCl03, KClO4 etc. are neutral salts.

To learn more about salts: brainly.com/question/5306491

#SPJ4

4 0
1 year ago
Calculate the molar solubility of CaCO3 in 0.250M Na2CO3<br><br> Kps CaCO3 is 4.96x10-9
Yuliya22 [10]

Answer:

solubility is 1.984x10⁻⁹M

Explanation:

When CaCO₃ is in water, the equilibrium that occurs is:

CaCO₃(s) ⇄ Ca²⁺(aq) + CO₃²⁻(aq)

Kps = [Ca²⁺] [CO₃²⁻] = 4.96x10⁻⁹

If you have a 0.250M solution of Na₂CO₃, [CO₃²⁻] = 0.250M:

[Ca²⁺] [0.250M] = 4.96x10⁻⁹

Assuming you are adding an amount of CaCO₃:

[X] [0.250 + X] = 4.96x10⁻⁹

<em>Where X is the amoun of CaCO₃ you can add, that means, solubility</em>

X² + 0.250X - 4.96x10⁻⁹ = 0

Solving for X:

X = -0.25M → False answer, there is no negative concentrations.

X = 1.984x10⁻⁹M.

That means, <em>solubility is 1.984x10⁻⁹M</em>

3 0
3 years ago
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A selectively permeable membrane separates solution a and
Yakvenalex [24]
The water molecules will flow from b to a due to osmosis.

Osmosis is where water molecules will flow from a region of higher water potential to a region of lower water potential, through a selectively permeable membrane.

When the water molecule concentration is higher, it has a higher water potential top. Water potential is the tendency for them to flow to a lower region.

The net movement will stop until both sides of the solution has a same water potential.
3 0
3 years ago
M= 2 kg, a = 2 m/s^2. <br><br> Find F
saul85 [17]

Answer:

<h3>F=4k.gm/s^2</h3>

Explanation:

<h3>F=m×a</h3><h3>f=2k.g×2m/s^2</h3><h3>f=4k.gm/s^2</h3>
8 0
3 years ago
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