Answer:
when sediments harden, extreme pressure increase the temperature and then take time to alter to metamorphic rocks. <3~
Answer:
The correct answer is option C. The unknown solution definitely has Hg22+ present.
Explanation:
In the analysis of group 1 metal cation, the unknown solution is treated with sufficient quantity of 6 M HCl solution and if group 1 metal cations are present then white precipitate of Agcl, PbCl2 or Hg2Cl2 is formed. The precipitate of PbCl2 is soluble in hot water but the other two remains insoluble after treating with hot water. Precipitate of AgCl disappears upon treatment of NH3 solution but Hg2Cl2 becomes black in the reaction with NH3. The black Colour appears due to the formation of metallic Hg.
Balanced chemical equation of the reation is -
Hg2Cl2 + 2NH3 ---------> HgNH2Cl (white ppt.) + Hg (black ppt.) + NH4Cl
Therefore, from the given information the conclusion which can be drawn is that the unknown solution definitely has Hg22+ present.
Assuming that the number of mols are constant for both conditions:

Now you plug in the given values. V_1 is the unknown.

Separate V_1

V= 162.782608696 L
There are 2 sig figs
V= 160 L
Explanation:
A change that does not cause any change in chemical composition of a substance is known as a physical change.
For example, mass, density, volume etc are all physical changes.
On the other hand, a change that brings change in chemical composition of a substance is known as chemical change.
For example, combustion, toxicity, reactivity etc are all chemical changes.
Hence, following statements are identified as chemical or physical changes as follows.
(a) Oxygen gas supports combustion : Chemical change
(b) Fertilizers help to increase agricultural production : Chemical change
(c) Water boils below
on top of a mountain : Physical change
(d) Lead is denser than aluminum : Physical change
(e) Uranium is a radioactive element : Chemical change
Answer:
<u>the reaction will shift to the left </u>and produce more reactants
Explanation:
Step 1: data given
Kc = 190
Temperature = 1000 K
[CO] = 0.025 M
[H2] = 0.045 M
[H2O] = 0.025 M
[CH4] = 0.046 M
When Q=Kc, the system is at equilibrium and there is no shift to either the left or the right.
When Q<Kc, there are more reactants than products. As a result, some of the reactants will become products, causing the reaction to shift to the right.
When Q>Kc, there are more products than reactants. To decrease the amount of products, the reaction will shift to the left and produce more reactants
Step 2: The balanced equation
CO(g) + 3 H2(g) ⇌ H2O(g) + CH4(g)
Step 3: calculate Q
Q = [H2O][CH4] / [CO][H2]³
Q = (0.025*0.046) / (0.025*0.045³)
Q = 504.8
Q > Kc
This means there are more products than reactants. To decrease the amount of products, <u>the reaction will shift to the left </u>and produce more reactants