If a 22. 5 mm copper (ii) solution(solution a) had an absorbance of 1. 65. Then, the absorbance if 8 ml of solution a was used to prepare a 20. 0 ml of a new copper (ii) solution is 918.84.
According to Beer-Lambert law, the absorbance (A) of a substance depends on its concentration (c)
A = ε . l. c
where,
ε: absorptivity of the species
l: optical path length
A 22.5 mM phosphate solution (solution A) had an absorbance of 1.012.
A = ε . l . c
1.65 = ε . l . 22.5 mM
ε . l = 37.125 mM⁻¹
We will calculate the concentration of the second solution using the dilution rule.
C₁ . V₁ = C₂ . V₂
22.5mM . 8 mL = C₂ . 20.0 mL
C₂ = 24.75 mM
The absorbance of the second solution is:
A = (ε . l ). c
A = (37.125 mM⁻¹) x 24.75 mM = 918.84
Thus, we find that the value of absorbance is 918.84.
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Metals are used in many products because of the characteristic properties that most metals have. The product that requires the high luster of metals is a mirror. Luster is used to describe something that reflect light off a surface. Metals are known to have the quality of reflecting light from its surface therefore it is a good material for the said product.
Answer: 0.0 grams
Explanation:
To calculate the moles, we use the equation:
a) moles of butane
b) moles of oxygen
According to stoichiometry :
2 moles of butane require 13 moles of
Thus 0.09 moles of butane will require = of
Butane is the limiting reagent as it limits the formation of product and oxygen is present in excess as (1.02-0.585)=0.435 moles will be left.
Thus all the butane will be consumed and 0.0 grams of butane will be left.
It’s c because beryllium is light