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lys-0071 [83]
2 years ago
12

Please I need help with the question

Mathematics
2 answers:
liq [111]2 years ago
8 0

Answer:

b

Step-by-step explanation:

Likurg_2 [28]2 years ago
6 0
Split the figure into three shapes: right triangle no.1, rectangle, and right triangle no.2.

rectangle:
A = l × w
A = 3 × 11
A = 33 cm²

right triangle no.1 (on the left of the rectangle):
find leg 1 first: 17 - 11 = 6
A = ab/2
A = 6 × 3/2
A = 9 cm²

right triangle no.2 (on the right on the rectangle):
A = ab/2
A = 3 × 1/2
A = 1.5 cm²

Add:
33 + 9 + 1.5 = 43.5 cm² (choice b)
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Is (0, 2) a solution to the equation y=3x​
igor_vitrenko [27]

Answer:

no

Step-by-step explanation:

y = 3x

Substitute the point into the equation

2 = 3*0

2 =0

This is not true so the point is not a solution

6 0
3 years ago
Read 2 more answers
Choose 3 values for x that would make this inequality true. <br> X - 4&lt;20
Sergio039 [100]

Answer:

X= 23, 22, 21, 20, 19, 18, 17 and so forth

Step-by-step explanation:

To make this inequality true then "X-4" would have to be less than 20, not equal or more than. 24-4=20 meaning the basis for the answer of X would start at 23

6 0
3 years ago
Which equation below gives an incorrect value for the function k(x) = 512 x ?
Rus_ich [418]
The function is  k(x) = 512 · x .

Try 'A':      k(2/3) = (512) · (2/3) =  341.33...   not 64

Try 'B':      k(4/9) = (512) · (4/9) =  257.55...    not 16  

Try 'C':      k(1/3) = (512) · (1/3) =  170.66...    not 8

Try 'D':      k(2/9) = (512) (2/9) =  113.77...    not 8 .

So far, it looks like NONE of the choices is correct.

But wait !  There's more !

What if the actual function is                   k(x)  =  512ˣ
that is,  512 raised to the 'x' power ?
That would be a horse of a different cruller.

Let's try THAT out.

First, here are two facts that we'll need:

         ==>  512 ^ 1/3  =  8
and
         ==>  512 ^ 1/9  =  2 .

OK. NOW ...

Try 'A':  k(2/3) = (512) ^ 2/3  =  8^2 = 64             yes !

Try 'B':  k(4/9)  =  (512) ^ 4/9  =  2^4  =  16        yes !

Try 'C':  k(1/3)  =  (512) ^ 1/3  =  8                      yes !

Try 'D':  k(2/9)  =  (512) ^ 2/9  =  2^2  =  4  not  8 .

So here's what we have learned:

-- The function in the question is actually    k(x) = 512 ^ x

-- Choice-D is the incorrect one.
5 0
3 years ago
An equation of an ellipse is given. y2 = 1 − 3x2 (a) Find the vertices, foci, and eccentricity of the ellipse. vertex (x, y) = (
oksian1 [2.3K]

Answer:

Step-by-step explanation:

Given

y^2=1-3x^2

3x^2+y^2=1

\frac{x^2}{(\frac{1}{\sqrt{3}})^2}+\frac{y^2}{1}=1

therefore it is a vertical ellipse

thus a=1

b=\frac{1}{\sqrt{3}}

eccentricity of Ellipse

e^2=1-\frac{b^2}{a^2}

e^2=1-\frac{1}{(\sqrt{3})^2}

e^2=1-\frac{1}{3}

e^2=\frac{2}{3}

e=\sqrt{\frac{2}{3}}

Focii are (0,ae) and (0,-ae)

ae=1\times \sqrt{\frac{2}{3}}

thus focii are (0,\sqrt{\frac{2}{3}}) & (0,-\sqrt{\frac{2}{3}})

(b) Length of major axis =2a=2\times 1

length of minor axis=2b=2\times \sqrt{\frac{2}{3}}=2\cdot \sqrt{\frac{2}{3}}

8 0
3 years ago
What are the x-intercepts of the graph of the quadratic function f(x) = 3(x − 1)(x + 3)?
creativ13 [48]

Answer:

-3, 1

Step-by-step explanation:

f(x) = 3(x − 1)(x + 3)

To find the x intercepts, set the equation equal to zero

0 = 3(x − 1)(x + 3)

Using the zero product property

x-1 = 0     x+3 =0

x=1            x=-3

6 0
3 years ago
Read 2 more answers
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