All categories

3 years ago

Need help pleaseeeee

Physics

1 answer:

aniked [119]3 years ago

4 0

You have to move the paper up more because I can't really see the answer choice. I can see the diagram though.

You might be interested in

Consider a 24.0 V storage battery that can transfer, over the course of its useful lifetime, a total charge equivalent to 340000

xeze [42]

Answer:

Explanation:

Given that,

Potential difference of battery is

V = 24V

Total charge battery can transferred

q = 340,000C

Work done by the battery?

Work done is given as

W = qV

Where q is charge in Columbs

V is potential difference in Volts

Then, W = qV

W = 340,000×24

W = 8,160,000 J

Work done by the battery over it's useful life time is 8,160,000J

5 0

3 years ago

Suppose 1.4 mol of an ideal gas is taken from a volume of 2.5 m3 to a volume of 1.0 m3 via an isothermal compression at 27°C. (a

zysi [14]

Answer:

Part a)

Q = 3198 J

Part b)

It is compression of gas so this is energy transferred to the gas

Explanation:

Part a)

Energy transfer during compression of gas is same as the work done on the gas

In isothermal process work done is given by the equation

$W = nRT ln(\frac{V_2}{V_1})$

now we know that

n = 1.4 moles

T = 27 degree C = 300 K

$V_2 = 2.5 m^3$

$V_1 = 1 m^3$

now we have

$W = (1.4)(8.31)(300)(ln\frac{2.5}{1})$

$Q = 3198 J$

Part b)

It is compression of gas so this is energy transferred to the gas

6 0

4 years ago

The quantity x to be determined from the equation X=P-Q.

Softa [21]

Answer:

the correct answer will be 6.82 %that is 7%

p(1.27)-q(0.83) =x=0.44

0.02+0.01 =0.03 (maximum uncertainty)

percentage uncertainty =0.03/0.44×100 %

=6.82%

=7%

Explanation: it was d on my end

5 0

2 years ago

Glucose typically enters the cell through which mechanisms

Viktor [21]

Answer:

facilitated diffusion

3 0

3 years ago

"The International Space Station (ISS) orbits at a distance of 350 km above the surface of the Earth. (a) Determine the gravitat

vagabundo [1.1K]

Answer:

(a) g = 8.82158145 $m/s^2$ .

(b) 7699.990192m/s.

Explanation:

(a) Strength of gravitational field 'g' by definition is

$g = \frac{M_{(earth)} }{r^2} G$ , here G is Gravitational Constant, and r is distance from center of earth, all the values will remain same except r which will be radius of earth + altitude at which ISS is in orbit.

r = 6721,000 meters, putting this value in above equation gives g = 8.82158145 $m/s^2$ .

(b) We have to essentially calculate centripetal acceleration that equals new 'g'.

$a_{centripetal}=\frac{V^2}{r} =g$ here g is known, r is known and v is unknown.

plugging in r and g in above and solving for unknown gives V = 7699.990192m/s.

(c) S = vT, here T is time period or time required to complete one full revolution.

S = earth's circumfrence , V is calculated in (B) T is unknown.

solving for unknown gives T = 5484.3301s = 1.5234hours.

3 0

3 years ago