Answer:
Velocity = v = 2.24m/s
Acceleration = a = 0.20m/s²
Explanation:
Please see attachment below.
Given
z=(−8 cosθ) and θ = 0.3t
z = -8Cos (0.3t)
V = dz/dt
a = v²/R.
Please see full solution below.
Answer:
The mass of the object is 15.0 kg
The weight of the object is 147.15 N
Explanation:
The mass of the object is the quantity of matter contained in the object or the measure of the its property of inertia.
The mass is constant through out the universe
The mass of the object is given as 15.0 kg
The weight of the object is the force of attraction of the Earth on the object
The weight is dependent on the interacting objects.
The weight of the object = The mass of the object × Acceleration due to gravity
Where;
The acceleration due to gravity, g = 9.81 m/s²
∴ The weight of the object = 15.0 kg × 9.81 m/s²= 147.15 N
The weight of the object = 147.15 N
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a) The acceleration of the car is
b) The new acceleration would be
Explanation:
a)
The acceleration of a body is equal to the rate of change of the velocity:
where
is the change in velocity
is the time interval considered
For the data of the car in this problem, we have:
is the initial velocity
is the final velocity
is the initial time
is the final time
Substituting, we find the acceleration:
b)
To solve this part, we can apply Newton's second law of motion, which states that the net force applied on a body is equal to the product between its mass and its acceleration:
where
F is the net force
m is the mass
a is the acceleration
The equation can be rewritten as
We observe that the acceleration is directly proportional to the force: therefore, if the force were cut in half, the acceleration will also halve. Therefore, the new acceleration would be
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