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3 years ago

The position of the plane as it ascends is given by r=[3ati-btj-(5d-ct)k]m, where a=2.50m/s, d=1.00km, b=0.050m/s, and c=75m/s.

Physics

1 answer:

enyata [817]3 years ago

4 0

Answer:

Explanation:

r = 3(2.50)ti - 0.050tj - (5(1000) - 75t)k m

r = 7.5ti - 0.050tj + (75t - 5000)k

a) r(0) = (0i, 0j, -5000k) m

v(0) = r'(0) = (7.5i, -0.050j, 75k)

a(0) = v'(0) = (0i, 0j, 0k)

b) r(30) = (225i, -1.5j, -2,750k) m

v(30) = (7.5i, -0.050j, 75k)

a(30) = (0i, 0j, 0k)

c) As velocity is not a function of time,

v(avg) = (7.5i, -0.050j, 75k)

d) As acceleration is not a function of time

a(avg) = (0i, 0j, 0k)

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The correct option is B.

There were 4 treatment conditions compared in the experiment.

F ratio plays an essential role in performing a particular dataset of ANOVA. F ratio is particularly a ratio which is obtained by the between-group variance or it is also called MSB and also within-group variance known as MSW. Any F-ratio which is computed is compared with the critical F-ratios from the table as it will check out if there are any variations available between the groups or not.

The researcher reports an F-ratio where the degrees of freedom = 3, 36.

F-ratio is obtained by the calculation of dividing the Mean squared errors because of the treatment by the Mean squared error which occurs due to error.

For the particular case, the researcher reports an F-ratio having degrees of freedom = 3, 36. It is indicating that the treatments are being distributed with degrees of freedom which is 3 and specified errors are distributed with degrees of freedom which is 36.

Let the treatments which were involved in the study can be denoted by k.

Let the total number of individuals involved in the study can be taken as N.

Then, the treatments will be having degrees of freedom as,

$df_{treatments}$ = k-1

3=k-1

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Therefore, the required treatment condition number that was compared is 4.

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1 year ago

A wall has inner and outer surface temperatures of 25◦C and 8◦C, respectively. The interior and exterior air temperatures are 35

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Answer:

a) $\frac{\dot Q}{A} =60\ W.m^{-2}$

b) $\frac{\dot Q}{A} =110\ W.m^{-2}$

c) The wall may not be under steady because the two surfaces of the wall are exposed to the air at different temperatures and they have different convective coefficient.

Explanation:

Given:

temperature of the inner surface of the wall, $T_i=25^{\circ}C$

temperature of the outer surface of the wall, $T_o=8^{\circ}C$

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coefficient of heat convection on inside, $h_i=6\ W.m^{-2}.K^{-1}$

The heat flux between the interior air and the wall:

The convective heat transfer rate is given as,

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$\frac{\dot Q}{A} =60\ W.m^{-2}$

The heat flux between the exterior air and the wall:

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$\frac{\dot Q}{A}=10\times (8-(-3))$

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