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aivan3 [116]
2 years ago
10

What are some ways to defend a castle against attack?

Physics
2 answers:
alexandr402 [8]2 years ago
6 0

Answer: how to defend

Explanation: building up high, have tall towers, battlements, arrow slits, moat, dungeons, and a drawbridge. (i hope this helped.)

ella [17]2 years ago
4 0

Answer:

you can build a mote around your castle and put crocodiles in it.

Explanation:

they will have to go in the water to get to your castle and will get eaten.

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Three boards, each 50 mm thick, are nailed together to form a beam that is subjected to a 1200-N vertical shear. Knowing that th
lisabon 2012 [21]

Answer:

Using equation

qs=F

q=VQ/I   V=1200

q=998.45 N

qs=F

s=F/q

s=700/998.45

spacing=s=0.701 m

7 0
3 years ago
Read 2 more answers
Based on the graph, which data point is most likely to have experimental
Len [333]

Answer:

B. 59 kg

Explanation:

From the graph you notice that a linear relation in indicated by the line joining the points such that the points on the line represent the data that show a correct relationship in the experiment.

This means that the point outside the line has an error .

This point is the value 59 kg that does not align with other values which are included in the graph.

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2 years ago
The volume of a gas at 400.0ml when the pressure is 1.00atm. at the same temperature, what is the pressure at which the volume o
Mila [183]

Answer:

5.025 atm

Change the 2.01 to ml then cross multiply

400/1= 2010/x

210/400=5.025

3 0
3 years ago
A colloidal liquid in a has is called
S_A_V [24]
Aerosol is the answer
8 0
3 years ago
Two forces F1 and F2 are acting on a block of mass m=1.5 kg. The magnitude of
nika2105 [10]

Answer:

Explanation:

Component of force F₁ in right direction = F₁cos37

= 12 x cos37 = 9.58 N .

Component of force F₂ in  vertically upward direction = F₁sin37

= 12 x sin37 = 7.22 N .

a ) Let normal force be R

R + F₁sin37  = mg

R + 7.22 = 1.5 x 9.8 = 14.7

R = 7.48 N .

b )

Net force in horizontal direction = F₂ - F₁cos37

= F₂ - 9.58

This is equal to zero as body is moving with zero acceleration

F₂ - 9.58 = 0

F₂ = 9.58 N

c ) If body is moving with acceleration of 2.5 m /s² along the direction of F₂

F₂ - 9.58 = 1.5 x 2.5 = 3.75

F₂ = 13.33 N .

6 0
3 years ago
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