Answer:
Explanation:
The 2 equations we need here are, first:
and then once we solve for the acceleration here:
Δx
Solving for acceleration:
and now we will use that in the other equation:
Δx and
36 = 16 + 
Δx and
20 = Δx and
Δx so
Δx = 50 m
Answer:
7808 m/s
Explanation:
Find NE velocity after 60 s of acceleration in that direction:
= a t = 28.4 m/s^2 * 60 s = 1704 m/s
Vertical component = 1704 sin 45 = 1204.9 m/s
Horiz component = 1704 cos 45 = 1204.9 m/s
Add the two vertical components
6510 + 1204.9 = 7714.9 m/s = vertical velocity
Pythagorean theorem to find resultant of vertical and horiz v's
Vf ^2 = 1204.9^2 + 7714.9^2 0
Vf = 7808. m/s
The time for the police car to catch up with the speeding motorist is 7.6 seconds.
<h3>What time will the police car catch up with the speeding motorist?</h3>
The police car and the motorist will cover equal distances.
Let the distance covered be d.
Distance covered by the motorist = speed * time
time = t, speed = 30 m/s
d = 30t
Distance covered by the police car = acceleration * (time)
time = t - 2, acceleration = 5.0 m/s²
d = 5(t-2)²
d = 5(t² - 4t + 4)
d = 5t² - 20t + 20
Equating the two equations for distance
5t² - 20t + 20 = 30t
5t² - 50t + 20 = 0
Solving for t using the quadratic formula:
t = 9.6 second or 0.4 seconds
Since t > 2, t = 9.6 seconds
t - 2 = 9.6 - 2
t - 2 = 7.6 seconds
Therefore, the time for the police car to catch up with the speeding motorist is 7.6 seconds.
Learn more about distance and acceleration at: brainly.com/question/14344386
#SPJ1
Answer:
Answers of the Both parts are in the following attachment
Explanation:
