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JulsSmile [24]
4 years ago
12

Sometimes voltage is also called A. electrical force. B. electrical potential. C. electrical resistance. D. electrical field ene

rgy.
Chemistry
2 answers:
Oliga [24]4 years ago
7 0
Voltage<span>, </span>also called<span> electromotive force, is a quantitative expression of the potential difference in charge between two points in an electrical field.

So ACTUALLY an "electromotive force", but of your answer choices.

D. Electrical Field Energy
</span>
Pani-rosa [81]4 years ago
6 0
A-electrical force..............
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Zn(s)+2 HCl(aq)→ZnCl2(aq)+H2(g)
Veronika [31]

The answer is 300,400

8 0
4 years ago
Solutions of sodium carbonate and silver nitrate react to form solid silver carbonate and a solution of sodium nitrate. A soluti
ella [17]

Answer :

The mass of excess mass of Na_2CO_3, AgNO_3,Ag_2CO_3\text{ and }NaNO_3 are, 1.908 g, 0 g, 12.144 g and 3.74 g respectively.

Explanation : Given,

Mass of Na_2CO_3 = 4.25 g

Mass of AgNO_3 = 7.50 g

Molar mass of Na_2CO_3 = 106 g/mole

Molar mass of AgNO_3 = 170 g/mole

Molar mass of Ag_2CO_3 = 276 g/mole

Molar mass of NaNO_3 = 85 g/mole

First we have to calculate the moles of Na_2CO_3 and AgNO_3.

\text{Moles of }Na_2CO_3=\frac{\text{Mass of }Na_2CO_3}{\text{Molar mass of }Na_2CO_3}=\frac{4.25g}{106g/mole}=0.040moles

\text{Moles of }AgNO_3=\frac{\text{Mass of }AgNO_3}{\text{Molar mass of }AgNO_3}=\frac{7.50g}{170g/mole}=0.044moles

Now we have to calculate the limiting and excess reagent.

The balanced chemical reaction is,

Na_2CO_3+2AgNO_3\rightarrow Ag_2CO_3+2NaNO_3

From the balanced reaction we conclude that

As, 2 moles of AgNO_3 react with 1 mole of Na_2CO_3

So, 0.044 moles of AgNO_3 react with \frac{0.044}{2}=0.022 moles of Na_2CO_3

From this we conclude that, Na_2CO_3 is an excess reagent because the given moles are greater than the required moles and AgNO_3 is a limiting reagent and it limits the formation of product.

The excess mole of Na_2CO_3 = 0.040 - 0.022 = 0.018 mole

Now we have to calculate the mass of excess mole of Na_2CO_3.

\text{Mass of }Na_2CO_3=\text{Moles of }Na_2CO_3\times \text{Molar mass of }Na_2CO_3=(0.018mole)\times (106g/mole)=1.908g

Now we have to calculate the moles of Ag_2CO_3.

As, 1 moles of AgNO_3 react to give 1 moles of Ag_2CO_3

So, 0.044 moles of AgNO_3 react to give 0.044 moles of Ag_2CO_3

Now we have to calculate the mass of AgCO_3.

\text{Mass of }Ag_2CO_3=\text{Moles of }Ag_2CO_3\times \text{Molar mass of }Ag_2CO_3=(0.044mole)\times (276g/mole)=12.144g

Now we have to calculate the moles of NaNO_3.

As, 2 moles of AgNO_3 react to give 2 moles of NaNO_3

So, 0.044 moles of AgNO_3 react to give 0.044 moles of NaNO_3

Now we have to calculate the mass of NaNO_3.

\text{Mass of }NaNO_3=\text{Moles of }NaNO_3\times \text{Molar mass of }NaNO_3=(0.044mole)\times (85g/mole)=3.74g

6 0
4 years ago
How do you make these equations balanced?
Sedaia [141]

Explanation:

both iron and sulphur in FeS2 undergo a change in oxidation state.

O2° -->2O degree2- Total decrease = 2×2=4

So, 4FeS2+11O2 --> 2Fe2O3+8 SO2

Hence, balanced

3 0
3 years ago
Define Each Piece of the Microscope
horrorfan [7]

1) Body tube (Head): The body tube connects the eyepiece to the objective lenses. Arm: The arm connects the body tube to the base of the microscope. Coarse adjustment: Brings the specimen into general focus. Fine adjustment: Fine tunes the focus and increases the detail of the specimen.

2)Microscopes are made up of lenses for magnification, each with their own magnification powers. Depending on the type of lens, it will magnify the specimen according to its focal strength.

3)In simple magnification, light from an object passes through a biconvex lens and is bent (refracted) towards your eye. ... The eyepiece lens usually magnifies 10x, and a typical objective lens magnifies 40x. (Microscopes usually come with a set of objective lenses that can be interchanged to vary the magnification.)

3 0
3 years ago
A round character is one-sided and does not show much of his/her emotions or conflicts.
My name is Ann [436]

Answer:

true

Explanation:

Round characters tend not to show a lot of their emotions or feelings.

7 0
3 years ago
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