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JulsSmile [24]
3 years ago
12

Sometimes voltage is also called A. electrical force. B. electrical potential. C. electrical resistance. D. electrical field ene

rgy.
Chemistry
2 answers:
Oliga [24]3 years ago
7 0
Voltage<span>, </span>also called<span> electromotive force, is a quantitative expression of the potential difference in charge between two points in an electrical field.

So ACTUALLY an "electromotive force", but of your answer choices.

D. Electrical Field Energy
</span>
Pani-rosa [81]3 years ago
6 0
A-electrical force..............
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Do ghosts exists ?? ...​
Nesterboy [21]

Answer:

no

Explanation:

it is human imagination about scary things that brought about ghost

5 0
3 years ago
7. List things that have LOTS of kinetic energy, and tell why.
vlabodo [156]

Answers: -

For high kinetic energy, the object must have high speed of movement.

1) An airplane has a lot of kinetic energy. Airplanes move at high speed and thus posses a lot of kinetic energy.

2) A bullet from a gun has a lot of kinetic energy due to the high speed of bullet.

3) A formula one car moving at high speeds have a lot of kinetic energy.

4) A train moving at high speed has lots of kinetic energy.

5) An asteroid has a lot of kinetic energy due to it's high speed.

6) A roller coaster moving at high speeds have a lot of kinetic energy.

7) A missile fired from a fighter plane has lots of kinetic energy.

7 0
3 years ago
Match each term with its definition. 1) reaction coordinate
Andreyy89
1) reaction coordinate is : <span>b.the plot of the reaction progress as a function of time
2) </span>ΔG⁰ : <span>c.the free energy of the reaction
3) </span>ΔG⁺+ : <span>a.the higher point on the energy curve</span>
3 0
3 years ago
In yeast, ethanol is produced from glucose under anaerobic conditions. A cell‑free yeast extract is placed in a solution that co
nadezda [96]

Answer:

0.35 milli moles of ethanol can be theoretically be produced under these conditions.

Explanation:

C_6H_{12}O_6 + 2 ADP + 2 Pi\rightarrow 2 C_2H_5OH + 2 ATP + 2 CO_2

Moles of glucose = 3.50\times 10^2 milli mole

Moles of ADP = 0.35 milli mole

Moles of Pi = 0.35 milli mole

Moles of ATP = 0.70 milli mole

As we can see that ADP and Pi are in limiting amount which means tat they are limiting reagent. So, the moles of ethanol produced will depend upon the moles of ADP and Pi.

According to reaction, 2 moles of ADP gives 2 moles of glucose.

Then 0.35 milli moles of ADp will give :

\frac{2}{2}\times 0.35 mmol=0.35 mmol of ethanol

0.35 milli moles of ethanol can be theoretically be produced under these conditions.

5 0
3 years ago
I need help on both a and b of question 1
marishachu [46]

Answer:

(a) -0.00017 M/s;

(b) 0.00034 M/s

Explanation:

(a) Rate of a reaction is defined as change in molarity in a unit time, that is:

r = \frac{\Delta c}{\Delta t}

Given the following reaction:

2 N_2O_5 (g)\rightleftharpoons 4 NO_2 (g) + O_2 (g)

We may write the rate expression in terms of reactants firstly. Since reactants are decreasing in molarity, we're adding a negative sign. Similarly, if we wish to look at the overall reaction rate, we need to divide by stoichiometric coefficients:

r = -\frac{\Delta [N_2O_5]}{2 \Delta t}

Reaction rate is also equal to the rate of formation of products divided by their coefficients:

r = \frac{\Delta [NO_2]}{4 \Delta t} = \frac{\Delta [O_2]}{\Delta t}

Let's find the rate of disappearance of the reactant firstly. This would be found dividing the change in molarity by the change in time:

r_{N_2O_5} = \frac{0.066 M - 0.100 M}{200.00 s - 0.00 s} = -0.00017 M/s

(b) Using the relationship derived previously, we know that:

-\frac{\Delta [N_2O_5]}{2 \Delta t} = \frac{\Delta [NO_2]}{4 \Delta t}

Rate of appearance of nitrogen dioxide is given by:

r_{NO_2} = \frac{\Delta [NO_2]}{\Delta t}

Which is obtained from the equation:

-\frac{\Delta [N_2O_5]}{2 \Delta t} = \frac{\Delta [NO_2]}{4 \Delta t}

If we multiply both sides by 4, that is:

-\frac{4 \Delta [N_2O_5]}{2 \Delta t} = \frac{\Delta [NO_2]}{\Delta t}

This yields:

[tex]r_{NO_2} = \frac{\Delta [NO_2]}{\Delta t} = -2\frac{\Delta [N_2O_5]}{ \Delta t} = -2\cdot (-0.00017 M/s) = 0.00034 M/s[tex]

5 0
3 years ago
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