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2 years ago

These waves are traveling at the same speed. Which wave has the highest frequency?

Physics

2 answers:

Leviafan [203]2 years ago

8 0

Answer: A

Explanation: The relation between velocity and frequency of the waves is:

f = v/λ

where f is frequency, v is the velocity and λ is the wavelenght.

So you can see that, if the 4 waves have the same velocity, then the one with the smallest wavelenght (because it is in the denominator) will have the highest frequency.

The one with the smallest frequency is the first one (you can see it) so the correct option will be A

Margaret [11]2 years ago

5 0

Answer:

A The shorter the wavelength the higher the frequency the longer the lower, hope this helps, thanks.

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A person exerts a tangential force of 37.7 N on the rim of a disk-shaped merry-go-round of radius 2.75 m and mass 144 kg. If the

Shkiper50 [21]

Answer:

ω = 0.467 rad/s

Explanation:

given,

tangential force exerted by the person = 37.7 N

radius of merry-go-round = 2.75 m

mass of merry-go-round = 144 Kg

angle = 33.2°

moment of inertia

$I = \dfrac{1}{2} m R^2$

$I = \dfrac{1}{2}\times 144 \times 2.75^2$

I = 544.5 kg.m²

torque = force x radius

τ = 37.7 x 2.75

τ = 103.675 N.m

angular acceleration

$\alpha= \dfrac{\tau}{I}$

$\alpha= \dfrac{103.675}{544.5}$

α = 0.190 rad/s²

now ,

distance = $33.2\times \dfrca{2\pi}{360}$

d = 0.579 rad

we know,

using equation of rotational motion

$d = \omega t + \dfrac{1}{2}\alpha t^2$

$0.579 = \dfrac{1}{2}\times 0.190\times t^2$

t = 2.46 s

angular speed

ω = α x t

ω = 0.19 x 2.46

ω = 0.467 rad/s

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A force of 500 N acts horizontally on a 10,000 g body. What is its horizontal acceleration

Paladinen [302]

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Murljashka [212]

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