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A cylindrical metal pipe has a diameter of 8.4 millimeters

Phoenix [80]

Answer:

C. 271.44 $mm^3$

Step-by-step explanation:

We need to first find the volume of the pipe, then find the volume of the hole and then subtract the volume of the hole from the volume of the pipe.

The diameter of the pipe is 8.4 mm. This means its radius is:

8.4/2 = 4.2 mm

The height of the pipe is 10 mm

The volume of a cylinder is given as:

$V = \pi r^2h$

where r = radius

h - height

Therefore, the volume of the cylinder without the hole is:

$V = \pi * 4.2^2 * 10\\\\V = 554.18 mm^3$

The diameter of the hole is 6 mm. Its radius is:

6/2 = 3 mm

The volume of the hole is:

$V = \pi * 3^2 * 10\\\\V = 282.74 mm^3$

The volume is:

554.18 - 282.74 = 271.44 $mm^3$

5 0

2 years ago

Read 2 more answers

The distance between 19 and -15 on a number line is 4?

Murrr4er [49]

Answer:

See explanation below.

Step-by-step explanation:

No.

The distance between 19 and 15 is 4. Both numbers are positive, 4 units apart.

The distance between -19 and -15 is also 4. Both numbers are negative, 4 units apart.

When you find the distance from 19 to -15, keep in mind that one number is positive, 19, and one number is negative, -15. The two numbers are on different side of zero on the number line.

Start at -15. -15 is 15 units to the left of zero. To get to 0, you need to go 15 units right. Now you need to go from 0 to 19. That is another 19 units right. Add 15 + 19 to get 34.

The distance from 19 to -15 on a number line is not 4. It is 34.

8 0

3 years ago

Math please help tutor :)

Fantom [35]

Answer:

8.5

Step-by-step explanation:

6 0

3 years ago

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Suppose a rectangular pasture is to be constructed using 1 2 linear mile of fencing. The pasture will have one divider parallel

timama [110]

Answer:

$\displaystyle A=\frac{1}{192}$

Step-by-step explanation:

<u>Maximization With Derivatives</u>

Given a function of one variable A(x), we can find the maximum or minimum value of A by using the derivatives criterion. If A'(x)=0, then A has a probable maximum or minimum value.

We need to find a function for the area of the pasture. Let's assume the dimensions of the pasture are x and y, and one divider goes parallel to the sides named y, and two dividers go parallel to x.

The two divisions parallel to x have lengths y, thus the fencing will take 4x. The three dividers parallel to y have lengths x, thus the fencing will take 3y.

The amount of fence needed to enclose the external and the internal divisions is

$P=4x+3y$