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2 years ago

Which is an example of Identity Property of Zero?

Mathematics

1 answer:

luda_lava [24]2 years ago

4 0

Answer:

Identity Property of Zero

The identity property of 0 states that if you add or subtract 0 from any number, the number will always stay the same. Here are some examples involving whole numbers: 3+0=3 7−0=7 Therefore, x+0=0+x=x. This is also known as the additive identity property of 0.

Step-by-step explanation:

Hope it helps :)

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A:Write (⅔)² in expanded form, B. And then evaluate.

KatRina [158]

Answer:

4/9

Step-by-step explanation:

(2/3)^2

(2/3) x (2/3)

2 x 2 is 4

3 x 3 is 9

4/9

4 0

2 years ago

6 ( f + 4 ) + 2 ( f + 4 )

Helga [31]

6(f+4) + 2(f+4)

Use the distributive property:

6f+24 + 2f + 8

Now combine like terms:

8f +32

The answer is 8f + 32

4 0

2 years ago

Read 2 more answers

Two functions are shown in the table below: Function 1 2 3 4 5 6 f(x) = −x2 + 4x + 12 g(x) = x + 2 Complete the table on your ow

zubka84 [21]

Answer:

x f(x) g(x)

1 15 3

2 16 4

3 15 5

4 12 6

5 7 7

6 0 8

f(x) = g(x) when x = 5

Step-by-step explanation:

f(x) = -x² + 4x + 12

f(1) = -(1)² + 4(1) + 12 = 15

f(2) = -(2)² + 4(2) + 12 = 16

f(3) = -(3)² + 4(3) + 12 = 15

f(4) = -(4)² + 4(4) + 12 = 12

f(5) = -(5)² + 4(5) + 12 = 7

f(6) = -(6)² + 4(6) + 12 = 0

g(x) = x + 2

g(1) = 1 + 2 = 3

g(2) = 2 + 2 = 4

g(3) = 3 + 2 = 5

g(4) = 4 + 2 = 6

g(5) = 5 + 2 = 7

g(6) = 6 + 2 = 8

3 0

2 years ago

ANSWER ASAP PLS Eve knits scarves for her online store. This week she has already knitted 9 scarves. There are 2 days left in th

JulsSmile [24]

Answer:

Step-by-step explanation:

Since Eve has already knitted nine scarves we just need to add of few more. Our equation is this: 9 + _ + _ = ?

If you do 9 + 4 + 4, you get 17. Therefor, Eve must knit four scarves per day to meet her goal.

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2 years ago

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The life, in years, of a certain type of electrical switch has an exponential distribution with an average life β=44. If 100 o

Bond [772]

Answer:

0.9999

Step-by-step explanation:

Let X be the random variable that measures the time that a switch will survive.

If X has an exponential distribution with an average life β=44, then the probability that a switch will survive less than n years is given by

$\bf P(X$

So, the probability that a switch fails in the first year is

$\bf P(X$

Now we have 100 of these switches installed in different systems, and let Y be the random variable that measures the the probability that exactly k switches will fail in the first year.

Y can be modeled with a binomial distribution where the probability of “success” (failure of a switch) equals 0.0225 and

$\bf P(Y=k)=\binom{100}{k}(0.02247)^k(1-0.02247)^{100-k}$

where

$\bf \binom{100}{k}$ equals combinations of 100 taken k at a time.

The probability that at most 15 fail during the first year is

$\bf \sum_{k=0}^{15}\binom{100}{k}(0.02247)^k(1-0.02247)^{100-k}=0.9999$

3 0

2 years ago