The Lorentz force acting on the proton is equal to:

where
q is the proton charge
v is the proton speed
B is the intensity of the magnetic field

is the angle between the direction of v and B
since the proton travels perpendicularly to the magnetic field, in this case

, so the Lorentz force in this case is simply

The magnetic force provides also the centripetal force that keeps the proton in circular motion:

where
m is the proton mas
r is the radius of the orbit
If we re-arrange this equation and we use the data of the problem, we can find the radius of the orbit:
Answer:
SI unit
Explanation:
The kilogram-meter per second (kg · m/s or kg · m · s -1 ) is the standard unit of momentum. Reduced to base units in the International System of Units ( SI ), a kilogram-meter per second is the equivalent of a newton-second (N · s), which is the SI unit of impulse .
Electronegativity<span> is a relative measure of how strongly an atom </span>will<span> attract the electrons in a bond</span>
Answer:
I think it should be C, which is one