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lora16 [44]
3 years ago
11

Can someone PLEASE help me I need to find the length of these two ladders, please actually help and don't just guess. If you can

show me how you did it too, i will give you brainliest

Mathematics
2 answers:
Lemur [1.5K]3 years ago
8 0

Answer:

As this is a right angled triangle, simply find the hypotenuse

Step-by-step explanation:

We know that the square of hypotenuse is equal to the sum of the square of the other two sides

In formula > h²=a²+b²

We know the values of a and b.

Now simply put the values into the equation to find the answer :)

For 1,  h²= 25² + 10²

h² = 625 + 100

=725

h=√(725)

=26.92 feet

Therefore height of ladder = 26.92 feet

For 2,

h²= 21²+20²

h²=441 + 400

h² = 841

h = √841

h = 29 feet

Heigh of ladder = 29 feet

Lina20 [59]3 years ago
4 0

Answer:

29 feet for second ladder

Step-by-step explanation: I dont think first is possibe(decimals), second 21 square+ 20 square= 441+200=881, root of 881 is 29.

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A rectangular pyramid. The rectangular base has a length of 10 inches and a width of 6 inches. 2 triangular sides have a base of
melisa1 [442]

Answer:

Answer:

a) The base of the rectangular pyramid shown has an area of

60 square inches

b) A triangular face with a base of 10 inches has an area of 28 square inches.

c) A triangular face with a base of 5 inches has an area of 17.75 square inches.

d) The total surface area of the pyramid is 151.5 square inches.

Step-by-step explanation:

a) Solving for question a, we were given the following parameters

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The formula used to calculate the rectangular base of a rectangular pyramid =

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Where :

Length = 10 inches

Width = 6 inches

Rectangular base = 10 inches × 6 inches

= 60 inches²

Hence, the base of the rectangular pyramid shown has an area of 60 square inches

b) Solving for question b, we have the following values given:

2 triangular sides have a base of 10 inches and height of 5.6 inches.

First step would be to solve for one triangular side first.

The area of the one triangular side = (Base × Height) ÷ 2

= (10 inches × 5.6 inches) ÷ 2

= 56inches² ÷ 2

= 28 inches²

Therefore, for the 2 triangular sides, since they have the same base and height, the other side as well would be 28 inches².

A triangular face with a base of 10 inches has an area of 28 square inches.

c) Solving for question c, the following parameters are given:

2 triangular sides have a base of 5 inches and height of 7.1 inches.

We would be to solving for one triangular side first.

The area of the one triangular side = (Base × Height) ÷ 2

= (5 inches × 7.1 inches) ÷ 2

= 35.5 inches² ÷ 2

= 17.75 inches²

Therefore, for the 2 triangular sides, since they have the same base and height, the other side as well would be 17.75 inches².

A triangular face with a base of 5 inches has an area of 17.75 square inches.

d) Solving for d, it is important to note that, a rectangular pyramid has 5 faces and they are: The rectangular base and 4 triangular faces

The formula for the total surface area of the rectangular pyramid is given as

Total Surface Area of the rectangular pyramid = Rectangular Base + Area of Triangular Side A + Area of Triangular Side B + Area of Triangular Side C + Area of Triangular Side D + Area of Triangular Side E

Total Surface Area of the Rectangular Pyramid = 60 inches² + 28 inches² + 28 inches² + 17.75 inches² + 17.75 inches²

Total surface Area of the Rectangular pyramid = 151.5 inches²

The total surface area of the pyramid is 151.5 square inches.

Step-by-step explanation:

BRAINLIEST PLEASE?

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lesantik [10]

Answer:

Step-by-step explanation:

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