I need the answer pls

All of these are true about steel EXCEPT that:

natta225 [31]

Answer:B) heat tends to strengthen high-strength steel.

Explanation: You are right it is B

3 0

2 years ago

What is bubble sort?what is bubble sort

juin [17]

Answer:

Bubble sort, sometimes referred to as sinking sort, is a simple sorting algorithm that repeatedly steps through the list, compares adjacent elements and swaps them if they are in the wrong order. The pass through the list is repeated until the list is sorted.

Explanation:

Look at the photo

Good luck

4 0

3 years ago

Read 2 more answers

How nany degrées is the included angle of General Purpose Acme threads? A. 60 B. 29 c. 14.5 D. 10

horrorfan [7]

Answer:

B.29

Explanation:

In general purpose acme thread:

Nominal depth of thread=0.5 $ltimes Pitch$

Included angle =29 degrees

Generally Acme thread are following types

1.General purpose(G) Acme

2.Centralizing(C) Acme

3. Stub Acme

Centralizing(C) Acme threads have tighter tolerance during manufacturing as compare to General purpose(G) Acme threads.

8 0

3 years ago

Iron has a BCC crystal structure, an atomic radius of 0.124 nm, and an atomic weight of 55.85 g/mol. Compute and compare its the

Andre45 [30]

Answer:

Explanation:

The density of the unit cell of a material, Iron in this case, has to be approximately equal with its experimental value of 7.87 g/cm³.

The density d = m/v, so what we need to do is calculate the volume of the unit cell and its mass and perform the calculation.

For a BCC crystal structure the length of the side of the cube is given by:

a = 4r/√3

where a is the atomic radius of Iron

first we will convert this radius to cm since we want the density in g/cm³:

0.124 nm x 1 x 10⁻⁷ cm / nm = 1.24 x 10⁻⁸ cm

a = 4 x 1.24 x 10⁻⁸ cm /√3 = 2.86 x 10⁻⁸ cm

the volume of the cubic cell is:

v = a³ = ( 2.86 x 10⁻⁸ cm )³ =2.35 x 10⁻²³ cm³

The mass of iron in the body centered cubic cell is obtained from the mass of the atoms in it:

BCC = 2 atoms / unit cell ( 1/8 from the 8 corners + 1 in the center)

m = 2 atoms/unit cell x 1 mol/ 6.022 x 10²³ atoms x 55.85 g/mol

= 1.85 x 10⁻²² g

Therefore,

d = m/v = 1.85 x 10⁻²² g / 2.35 x 10⁻²³cm³ = 7.88 g/cm³

An excelent agreement which confirms that the density of the BCC unit cell agrees with the experimental value.

4 0

4 years ago

A heat pump with refrigerant-134a as the working fluid is used to keep a space at 25°C by absorbing heat from geothermal water t

Leno4ka [110]

Answer:2.88

Explanation:

6 0

4 years ago

I need the answer pls​

I need the answer pls