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Natali [406]
3 years ago
8

A boat moves through the water of a river at 10m/s relative to the water, regardless of the boat ‘s direction . If the water in

the river is flowing at n1.50m/s , how long does it take the boat to make a round trip consisting of of 300m displacement downstream followed by a 300m displacement upstream?
Physics
1 answer:
katen-ka-za [31]3 years ago
8 0

Answer:

The appropriate solution is "61.37 s".

Explanation:

The given values are:

Boat moves,

= 10 m/s

Water flowing,

= 1.50 m/s

Displacement,

d = 300 m

Now,

The boat is travelling,

= 10+1.50

= 11.5 \ m/s

Travelling such distance for 300 m will be:

⇒ v = \frac{d}{t} \ sot \ t

      =\frac{d}{v}

On putting the values, we get

      =\frac{300}{11.5}

      =26.08 \ s

Throughout the opposite direction, when the boat seems to be travelling then,

= 10-1.50

= 8.5 \ m/s

Travelling such distance for 300 m will be:

⇒ v=\frac{v}{t} \ sot \ t

      =\frac{d}{v}

On putting the values, we get

      =\frac{300}{8.5}

      =35.29 \ s

hence,

The time taken by the boat will be:

= 26.08+35.29

= 61.37 \ s

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3 years ago
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two cars are travelling side by side down a straight road in opposite directions. both cars are travelling at a speed of 22 m/s.
Nimfa-mama [501]

Answer: 44m/s

Explanation:

Speed of Car A travelling left = 22m/s

Speed of Car B travelling right = 22m/s

Now recall that relative speed of objects moving in opposite directions is equal to the sum of each speed

Hence, Relative speed = (Speed of Car A + Speed of Car B)

= (22m/s + 22m/s)

= 44m/s

3 0
3 years ago
Newton’s first law says that if motion changes, then a force is exerted. Describe a collision in terms of the forces exerted on
ira [324]

Answer:

In collision between equal-mass objects, each object experiences the same acceleration, because of equal force exerted on both objects.

Explanation:

In a collision two objects, there is a force exerted on both objects that causes an acceleration of both objects. These forces that act on both objects are equal in magnitude and opposite in direction.

Thus, in collision between equal-mass objects, each object experiences the same acceleration, because of equal force exerted on both objects.

4 0
3 years ago
A proton traveling along the x-axis enters a region at x = 0 where the x-component of the electric field is given by E = Ao/x1/2
storchak [24]

.Answer:

The value of the work done is \bf{ 5.29 qA_{0}}.

Explanation:

When a charged particle having charge q is moving through an electric field E, the net force (F) on the charge is

F = qE~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(1)

and the work done (W) by the particle is

W = \int\limits^x_0 {F} \, dx ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(2)

Given, E = \dfrac{A_{0}}{x^{1/2}}.

Substitute the value of electric field in equation (1) and then substitute the result in equation (2).

W &=& \int\limits^7_0 {q\dfrac{A_{0}}{x^{1/2}}} \, dx \\&=& qA_{0} \int\limits^7_0 {x^{-1/2}} \, dx \\&=& 2qA_{0}[x^{1/2}]_{0}^{7}\\&=& 5.29 qA_{0}

7 0
3 years ago
Emily and Gemma did a Reaction time lab. Emily dropped the ruler while Gemma tried to catch it. She caught the ruler 5 times and
dlinn [17]

The average reaction time of Gemma is 0.1564 seconds.

As we know, Gemma is catching the scale and Emily is dropping the scale.

The whole experiment is taking place under gravity, so the acceleration is constant.

As we know, the scale is dropped, it means that the initial velocity of the scale is zero.

We can use the equation of motion,

The equation is,

S = Ut + 1/2at²

Where,

S is the displacement, which is 0.12 m in our case,

U is initial velocity which is 0m/s because the stone is dropped,

t is the time taken, this is equal tot he reaction time here,

a is the acceleration due to gravity whose value is 9.8m/s.

Now, putting all the values,

0.12 = 1/2(9.8)(t)²

t² = 0.24/9.8

t = 0.1564 seconds.

Gemma reacts in 0.1564 seconds to catch the scale.

To know more about equation of motion, visit,

brainly.com/question/27821888

#SPJ1

3 0
1 year ago
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