x max = (vi² sin 2α) / g
x max = (6.25² sin 90)/10
x max = 39.0625/10 = 3.91 m
Answer:
The wavelength of the laser, λ = 5.625 * 10⁻⁷ m
Explanation:
Separation of the narrow slits, d = 7.5 * 10⁻⁵ m
The distance between the screen and the two slits, d = 4m
The distance between the bright spot and the center of the pattern, Y = 1.5 cm
Y = 1.5 * 10⁻² m
To calculate the wavelength, λ, of the laser we will use the relationship:

λ = 5.625 * 10⁻⁷ m
Answer:
The longest wavelength of radiation is 241nm and it lies in ultraviolet region.
Explanation:
The minimum energy required to break o-o bond is 495kJ/mole.
The photon does not have mass and the energy of the single photon depends entirely on the wavelength and is given by
e =hc/λ
where, h is the Planck constant,
c is the speed of light
e is the energy of photon
λ is the wavelength
From the Planck formula we can understand that energy of the photon is quantized.
E = e.Nₐ
e = E/Nₐ =
= 8.22*10⁻¹⁹ J/photon
λ = hc/E= 
λ = 2.41*10⁻⁷ m = 241 nm
The longest wavelength of radiation is 241nm and it lies in ultraviolet region.
Answer:
Explanation:
1 ) Total mechanical energy of the car at the height of 10 m
1/2 mv² + mgh
.5 x 1800 x 25² + 1800 x 9.8 x 10 m
= 562500 + 176400
738900 J
If v be the velocity at the bottom ,
Total energy of the car at the bottom
1/2 m v² + 0
Applying conservation of energy
1/2 mv² = 738900
.5 x 1800 v² = 738900
v = 28.65 m /s
Energy required by car to ascend height of 15 m
1800 x 9.8 x 15
= 264600 J
b )
This energy is more that total energy of the car at the top that is 738900 J
so car can easily reach gas station .
If V be the velocity at the gas point
Total energy at the gas point
1/2 m V² + 264600
Applying conservation of energy
1/2 m V² + 264600 =738900
.5 x 1800 x V² = 474300
V = 22.95 m / s
d ) If R be the normal reaction at the bottom
net force
R - mg = m v² / r
R = m ( g + v² / r )
1800 ( 9.8 + 28.65² / 5 )
R = 313136 N