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slava [35]
3 years ago
14

Atoms have a tendency to complete their outer energy level. This is known as _____.

Chemistry
2 answers:
Debora [2.8K]3 years ago
6 0
Atoms have a tendency to complete their outer energy level. This is known as octet rule. That is because octet refers to 8 valence electrons, making a element stable in its outer shell. 
Alina [70]3 years ago
5 0

Answer : Option C) The Octet Rule

Explanation : Atoms have a tendency to complete their outer energy level. This is known as Octet Rule.

The octet rule is a chemical rule of thumb which reflects the observation, that atoms of main-group elements tends to combine in such a way that each atom gets eight electrons in its valence shell, which gives it the same electron configuration as that of a noble gas.

In short, the tendency of an atom to fill its valence shell and attain a stable state it acquires or donates the electron is called as octet rule.

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Question 5 (5 points)
Dima020 [189]

Answer:

They Are all O's/oberavtions, because inference is using facts and reasoning, which is not the case here.

Explanation:

6 0
2 years ago
Read 2 more answers
A gas at a constant volume has an initial temperature of 300.0 K and an initial pressure of 10.0 atm. What pressure does the gas
harkovskaia [24]
\frac{500}{300} times 10=16.667 atm
4 0
2 years ago
Please i need your help asap!
denis23 [38]

Answer:

Density is mass over volume.

Explanation:

6 0
2 years ago
How much heat is given off when 869 g iron bar cools from 94 degrees celsius to 5
melomori [17]

Answer:

Heat given off was -34.34kJ

Explanation:

Mass of iron bar = 869g

Initial temperature (T1) = 94°C

Final temperature (T2) = 5°C

Specific heat capacity of iron (c) = 0.444J/g°C

Heat energy (Q) = Mc∇T

Q = heat energy

c = specific heat capacity

∇T = change in temperature

M = mass of the substance

Q = mc∇T

∇T = T2 - T1

Q = Mc(T2 -T1)

Q = 869 * 0.444 * (5 - 94)

Q = 385.836 * -89

Q = -34339.404J

Q = -34.34kJ

The heat given of was -34.34kJ

4 0
3 years ago
What does a student need to know about double bonds and triple bonds when predicting molecular geometry of molecules?
zhuklara [117]

This problem is asking for an explanation of what we need to know about double and triple bonds to successfully predict molecular geometries in molecules. At the end, one comes to the conclusion that double and triple bonds contribute to the degree in which an atom is bonded and they also determine the lone pairs, which, at the same time,  define the molecular geometry.

<h3>Molecular geometry:</h3>

In chemistry, molecules are not necessarily flat arrangements of atoms, yet they have specific bond angles, orientations and shapes, which define the molecular geometry. In such a way, we can use the VSEPR theory in order to know the molecular geometry of a molecule; however, we first need its Lewis structure or at least the number and type of bonds to do so.

Consider water and carbon dioxide; the former has two hydrogen to oxygen bonds (O-H) and 2 lone pairs because O has six valence electrons but just 2 are bonded to complete the octet, so 4 unpaired electrons lead to two lone pairs. On the other hand, the latter has two double bonds (C=O) and 0 lone pairs because carbon has four valence electrons and they are all bonded to complete the octet.

In such a way, one can see how the double bond affected the bonding in CO2 in contrast to the H2O; situation that also applies to triple bonds, because CO2 has a linear molecular geometry whereas water has a bent one (see attached picture)

Hence, one comes to the conclusion that double and triple bonds contribute to the degree in which an atom is bonded and they also determine the lone pairs, which, at the same time, define the molecular geometry.

Learn more about molecular geometry: brainly.com/question/7558603

Learn more about the VSEPR theory:  brainly.com/question/14225705

5 0
2 years ago
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