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Answer:
Therefore, the boiling points of the alkanes increase with molecular size. For isomers, the more branched the chain, the lower the boiling point tends to be. Van der Waals dispersion forces are smaller for shorter molecules and only operate over very short distances between one molecule and its neighbors.
The boiling points of the normal alkanes increase with increasing molecular weight (Table 3.3). As the molecular weight increases, London forces increase because more atoms are present to increase the surface area or the molecules.
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Answer:
79.14%
Explanation:
Given the equation : 2Fe2O3 + 3C 4Fe + 3C02
The theoretical yield of CO2 ; is 102.6g
Actual yield = 81.2 gram
Percentage yield = (actual yield / theoretical yield) * 100%
Percentage yield = (81.2 / 102.6) * 100%
Percentage yield = 0.7914230 * 100%
Percentage yield = 79.14%
Hence, tbe percentage yield of CO2 is 79.14%
Answer:
Explanation:
Edit the reaction by drawing all steps in the appropriate boxes and connecting them with reaction arrows. Add charges where needed. Electron flow arrows should start on the electron(s) of an atom or a bond and should end on an atom, bond, or location where a new bond should be created. Include all free radicals by right-clicking on an atom on the canvas and then using the Atom properties to select the monovalent radical.
Answer: The empirical formula of the metal sulfide is
.
Explanation:
Given: Mass of metal = 20.38 g
Mass of metal sulfide = 31.47 g
Moles is the mass of a substance divided by its molar mass.
So, moles of cobalt (molar mass = 59 g/mol) are as follows.

Moles of bromine (molar mass = 80 g/mol) are as follows.

Now, the ratio of number of moles of cobalt and number of moles of bromine are as follows.
Moles of Co : Moles of Br = 1 : 2
Hence, the empirical formula is
.
Thus, we can conclude that the empirical formula of the metal sulfide is
.