Q = 5637 J
C =4.814 J/KgºC
Temperature : 45.5ºC - 20.9º C = 24.6ºC
Q = m x C x T
5637 = m x 4.814 x 24.6
5637 = m x 118.4244
m = 5637 / 118.4244
m = 47.60 g
hope this helps!
Answer:
A) 4P + 5O₂ → 2P₂O₅
Explanation:
A) 4P + 5O₂ → 2P₂O₅
This equation is balanced. There are four phosphorus and ten oxygen atoms are on both side of equation.
B) 5P + 4O₂ → 2P₄O₅
This equation is not balanced. There are five phosphorus and eight oxygen atoms on left, eight phosphorus ten oxygen on right side of equation.
C) 2P + O₂ → P₂O₅
This equation is not balanced. There are two phosphorus, two oxygen atoms on left and two phosphorus five oxygen on right side of equation.
D) 4P + 2O₂ → 2P₄O₅
This equation is not balanced. There are four phosphorus, four oxygen atoms on left and eight phosphorus ten oxygen on right side of equation.
Answer:
2H+ + SO4^2- +2Na+ + 2OH- ------------> 2Na+ + SO4^2- + 2H2O
Explanation:
In writing ionic reaction equations, we omit spectator ions, that is, ions that do not participate actively. Both the reactants and products are broken up into their constituent ions and a balanced equation involving ions only is written. Ionic equation balance usually require good knowledge of the reaction and nature of the reactants The dissolved compounds only are written as ions.
<u>Answer:</u> The actual yield of the carbon dioxide is 47.48 grams
<u>Explanation:</u>
For the given balanced equation:
To calculate the mass for given number of moles, we use the equation:
Theoretical moles of carbon dioxide = 1.30 moles
Molar mass of carbon dioxide = 44 g/mol
Putting values in above equation, we get:
To calculate the theoretical yield of carbon dioxide, we use the equation:
Theoretical yield of carbon dioxide = 57.2 g
Percentage yield of carbon dioxide = 83.0 %
Putting values in above equation, we get:
Hence, the actual yield of the carbon dioxide is 47.48 grams
