Iron (II) oxide is composed of iron with an oxidation number of +2 (shown by the II after iron) and an oxygen that has an oxidation number of -2 (oxygen almost always has an oxidation state of -2). Since the anion and cation both have a charge of +or- 2, they bond with each other with a 1 to 1 ratio and the formula should be FeO
I hope this helps. Let me know if anything is unclear.
<em>K</em> = 2.4 × 10^(-72)
<em>Step 1</em>. Determine the <em>value of n
</em>
Zn^(2+) + 2e^(-) → Zn
2Cl^(-) → Cl_2 + 2e^(-)
Zn^(2+) + 2Cl^(-) → Zn + Cl_2
∴ <em>n</em> = 2
<em>Step 2</em>. Calculate <em>K</em>
log<em>K</em> = <em>nE</em>°/0.0592 V = [2 × (-2.12 V)]/0.0592 V = -71.62
<em>K</em> = 10^(-71.62) = 2.4 × 10^(-72)
Does that make sense? I believe that’s what it is asking for.
Answer:
to understand the human life
Explanation:
hope this helps :)