<u>Answer:</u> The concentration of required will be 0.285 M.
<u>Explanation:</u>
To calculate the molarity of , we use the equation:
Moles of = 0.016 moles
Volume of solution = 1 L
Putting values in above equation, we get:
For the given chemical equations:
Net equation:
To calculate the equilibrium constant, K for above equation, we get:
The expression for equilibrium constant of above equation is:
As, is a solid, so its activity is taken as 1 and so for
We are given:
Putting values in above equations, we get:
Hence, the concentration of required will be 0.285 M.
Answer:
<h3>The answer is option C</h3>
Explanation:
The mass of a substance when given the density and volume can be found by using the formula
<h3>mass = Density × volume</h3>
From the question
volume of liquid = 15 mL
density = 2.5 g/mL
We have
mass = 15 × 2.5
We have the final answer as
<h3>37.5 g</h3>
Hope this helps you
Sedimentary rocks. Not sure though
Troposphere is the highest layer of the atmosphere and touches space
Startophere is where stratus clouds form up high in the sky
The Mesosphere is the third layer you need to know and it’s low density ...yo?
Thermosphere we’re getting closer and closer to earth
Exoshpere were airplanes are high, buckle up it’s time to fly
Answer:
Explanation:
When adding or subtracting values, you must round your answer to the same "place" as the measurement with its last significant figure furthest to the left.
That is, you round off to the same number of decimal places as the measurement with the fewest decimal places.
The measurement of 28.1 cm has one digit after the decimal point, so you round the sum to have only one digit to the right of the decimal.
However, the number to be dropped (51) is greater than 5 with only zeros or nothing following the 5.
You must round up the answer. You increase the last significant digit by one.