Answer:
<em></em>![\left[\begin{array}{ccc}2&-6&2\\0&3&-2\\0&2&2\end{array}\right] \left[\begin{array}{ccc}x\\y\\z\end{array}\right]= \left[\begin{array}{ccc}1\\-5\\-3\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D2%26-6%262%5C%5C0%263%26-2%5C%5C0%262%262%5Cend%7Barray%7D%5Cright%5D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Dx%5C%5Cy%5C%5Cz%5Cend%7Barray%7D%5Cright%5D%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%5C%5C-5%5C%5C-3%5Cend%7Barray%7D%5Cright%5D)
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Step-by-step explanation:
Given system of equations are
2x-6y-2z = 1
3y - 2z = -5
2y + 2z = -3
given
2 x - 6 y - 2 z = 1
0 x + 3 y - 2z = -5
0 x +2y + 2 z = - 3
<em>The Matrix form of the given system of equations </em>
<em>A X = B</em>
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X+y=90
x<2y
x+y< 3y
but x+y=90
90<3y
⇒ y>30
for example y=31, then x= 59
y=32, x= 58
.............................................
y=40, x=50
Step-by-step explanation:
you flip it from the line, match the letters (Z woube be C, X would be A, etc.) and then writw the new coordinates
I think that the answer is d
