First, set the equation in exponential form.
x=logbY to b^x=Y
x=log44. so x=x, b=10, Y=44
10^x=44
I know that 10^1=10, 10^2=100, and 10^1.5=31.6 so x should be between 1.5 and 2.
The answer is x=1.64.
X = 29 and y = 101.
To find this, you need to set up an equation.
6x - 95 = 79. Once you solve this, x would equal 29.
Since 6x - 95 and y are on a straight line, they would have to equal 180. So you make another equation except you plug in 29 for x this time.
6(29) - 95 + y = 180. Once you solve this, y would equal 101.
Answer:
x = 18 y = 10
Step-by-step explanation:
let the first number be x
let the second number be y
x = y + 8..... equation 1
2x + y = 46.... equation 2
x is the larger number
y is the smaller number.
Rearrange the equation and add equation 1 to equation 2.
x - y = 8
+ 2x + y = 46
-------------------
3x + 0 = 54
3x = 54
divide both sides by 3
x = 54/3
x = 18
Substitute x = 18 into equation 1
x = y + 8
18 = y + 8
collect like terms
y = 18-8
y = 10
