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Basile [38]
2 years ago
14

Reaction of an alkene with H2 to form an alkane is an example of a(n) _____ reaction because there is a(n) _____ in the number o

f C-H bonds. Multiple choice question. reduction, increase reduction, decrease oxidation, increase oxidation, decrease
Chemistry
1 answer:
AfilCa [17]2 years ago
6 0

Reaction of an alkene with H2 to form an alkane is an example of <u>reduction</u> reaction because there is an <u>increase</u> in the number of C-H bonds.

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Sunlight? air? i’m not sure they could all be matter..
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A student wants to make a fair comparison of the reactivity of the metals with hydrochloric acid.
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Answer:

the concentration of the reactants

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2 years ago
A gas mixture with a total pressure of 745 mmHg contains each of the following gases at the indicated partial pressures: CO2, 24
Setler79 [48]

<u>Answer:</u>

<u>For Part A:</u> The partial pressure of Helium is 218 mmHg.

<u>For Part B:</u> The mass of helium gas is 0.504 g.

<u>Explanation:</u>

  • <u>For Part A:</u>

We are given:

p_{CO_2}=245mmHg\\p_Ar}=119mmHg\\p_{O_2}=163mmHg\\P=745mmHg

To calculate the partial pressure of helium, we use the formula:

P=p_{CO_2}+p_{Ar}+p_{O_2}+p_{He}

Putting values in above equation, we get:

745=245+119+163+p_{He}\\p_{He}=218mmHg

Hence, the partial pressure of Helium is 218 mmHg.

  • <u>For Part B:</u>

To calculate the mass of helium gas, we use the equation given by ideal gas:

PV = nRT

or,

PV=\frac{m}{M}RT

where,

P = Pressure of helium gas = 218 mmHg

V = Volume of the helium gas = 10.2 L

m = Mass of helium gas = ? g

M = Molar mass of helium gas = 4 g/mol

R = Gas constant = 62.3637\text{ L.mmHg }mol^{-1}K^{-1}

T = Temperature of helium gas = 283 K

Putting values in above equation, we get:

218mmHg\times 10.2L=\frac{m}{4g/mol}\times 62.3637\text{ L.mmHg }mol^{-1}K^{-1}\times 283K\\\\m=0.504g

Hence, the mass of helium gas is 0.504 g.

6 0
3 years ago
How many grams of mercury can be produced if 18.0 g of mercury (11) oxide decomposes?
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Answer:

18.0 g of mercury (11) oxide decomposes to produce 9.0 grams of mercury

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2HgO ----> 2Hg + O₂

2 moles of HgO decomposes to produce 1 mole of Hg

2 moles of HgO has a mass of 433.2 g

433.2 g of HgO produces 216.6 g of Hg

18.0 of HgO will produce 18 × 216.6/433.2 g of Hg = 9.0 g of Hg

Therefore, 18.0 g of mercury (11) oxide decomposes to produce 9.0 grams of mercury

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2 years ago
What is the percent composition by mass of chlorine in LiCI
Lelechka [254]

Answer: Lithium (Li) 16.373%

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Explanation:

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