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Genrish500 [490]
3 years ago
11

In the lead storage battery, what are the charges on the lead species that are reactants or products in reactions that take plac

e at the anode and cathode?
A) 2+ and 4+
B) 0 and 2+
C) 0 and 4+
D) 0, 2+ and 4+
E) 0, 2+ 3+ and 4+
Chemistry
1 answer:
Aleksandr-060686 [28]3 years ago
5 0

Answer:

D) 0, 2+ and 4+

Explanation:

Lead storage battery consists of metallic lead and lead(IV)oxide in a bath of sulphuric acid.

The negative plate (Cathode) consists of metallic lead in the battery while the positive plate (Anode) consists of Lead(IV)Oxide (PbO2). The liquid in which these plates are suspended in is an aqueous medium of Sulphuric acid (H2SO4).

Negative plate reaction: Pb(s) + HSO4–(aq) → PbSO4(s) + H+(aq) + 2e–

Positive plate reaction: PbO2(s) + HSO4–(aq) + 3H+(aq) + 2e– → PbSO4(s) + 2H2O(l)

Combining these two reactions, one can determine the overall reaction:

Pb(s) + PbO2(s) + 2H+(aq) + 2HSO4–(aq) → 2PbSO4(s) + 2H2O(l)

Pb is in 0 valent state. PbO2 has Pb with 4+ valency. PbSO4 has Pb with 2+ valency.

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Catalyst
Hoochie [10]

a. volume of NO : 41.785 L

b. mass of H2O : 18 g

c. volume of O2 : 9.52 L

<h3>Further explanation</h3>

Given

Reaction

4 NH₃ (g) + 5 O2 (g) → 4 NO (g) + 6 H2O (l)

Required

a. volume of NO

b. mass of H2O

c. volume of O2

Solution

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\tt \dfrac{15}{22.4}=0.67~mol

mol ratio NH3 : H2O from equation : 4 : 6, so mol H2O :

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\tt mass=mol\times MW=1\times 18=18~g

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\tt n=\dfrac{PV}{RT}=\dfrac{1\times 35.5}{0.08206\times 1273}=0.34

mol ratio of NO : O2 = 4 : 5, so mol O2 :

\tt \dfrac{5}{4}\times 0.34=0.425

Volume O2 at STP :

\tt 0.425\times 22.4=9.52~L

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