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Genrish500 [490]
3 years ago
11

In the lead storage battery, what are the charges on the lead species that are reactants or products in reactions that take plac

e at the anode and cathode?
A) 2+ and 4+
B) 0 and 2+
C) 0 and 4+
D) 0, 2+ and 4+
E) 0, 2+ 3+ and 4+
Chemistry
1 answer:
Aleksandr-060686 [28]3 years ago
5 0

Answer:

D) 0, 2+ and 4+

Explanation:

Lead storage battery consists of metallic lead and lead(IV)oxide in a bath of sulphuric acid.

The negative plate (Cathode) consists of metallic lead in the battery while the positive plate (Anode) consists of Lead(IV)Oxide (PbO2). The liquid in which these plates are suspended in is an aqueous medium of Sulphuric acid (H2SO4).

Negative plate reaction: Pb(s) + HSO4–(aq) → PbSO4(s) + H+(aq) + 2e–

Positive plate reaction: PbO2(s) + HSO4–(aq) + 3H+(aq) + 2e– → PbSO4(s) + 2H2O(l)

Combining these two reactions, one can determine the overall reaction:

Pb(s) + PbO2(s) + 2H+(aq) + 2HSO4–(aq) → 2PbSO4(s) + 2H2O(l)

Pb is in 0 valent state. PbO2 has Pb with 4+ valency. PbSO4 has Pb with 2+ valency.

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We will use Arrehenius equation

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R = gas constant = 8.314 J / mol K

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A = frequency factor

ln A = ln (1.5×10 ^11) = 25.73

Ea = activation energy = 56.9 kj/mol = 56900 J / mol

lnK = 25.73 - (56900 / 8.314 X 298) = 2.76

Taking antilog

K = 15.8



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Evgesh-ka [11]

Answer:

             287.30 g of FeCO₃

Solution:

The Balance Chemical Equation is as follow,

                           FeCl₂ + Na₂CO₃    →    FeCO₃ + 2 NaCl

Step 1: Calculate Mass of FeCl₂ as,

                            Molarity  =  Moles ÷ Volume

Solving for Moles,

                            Moles  =  Molarity × Volume

Putting Values,

                            Moles  =  2 mol.L⁻¹ × 1.24 L

                           Moles  =  2.48 mol

Also,

                            Moles  =  Mass ÷ M.Mass

Solving for Mass,

                            Mass  =  Moles × M.Mass

Putting Values,

                            Mass  =  2.48 mol × 126.75 g.mol⁻¹

                            Mass =  314.34 g of FeCl₂

Step 2: Calculate Mass of FeCO₃ formed as,

According to equation,

          126.75 g (1 mole) FeCl₂ produces  =  115.85 g (1 mole) FeCO₃

So,

               314.34 g of FeCl₂ will produce  =  X g of FeCO₃

Solving for X,

                     X =  (314.34 g × 115.85 g) ÷ 126.75 g

                     X =  287.30 g of FeCO₃

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