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3 years ago

Please helppppp asap

Mathematics

2 answers:

Stolb23 [73]3 years ago

7 0

Answer:

Step-by-step explanation:

A results in p^2 -3p - 10

B results in p^2 -3p - 10

C results in p^2 - 7p + 10

so none of these are correct

D is the correct answer

hodyreva [135]3 years ago

5 0

Answer C

When you multiply that together (c), it gives you p^2, -5p, -2p, and 10. Add the -5-2, and it gives you -7, or the original equation.

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X^4-28x^2=0 solve algebraically

Paha777 [63]

$x^4 - 28x^2 = 0$

$x^2(x^2 - 28) = 0$

$x^2 = 0 \ \ or \ \ (x^2 - 28) = 0$

$x = 0 \ \ or \ \ x^2 = 28$

$x = 0 \ \ or \ \ x = \pm \sqrt{28}$

$x = 0 \ \ or \ \ x = \pm2 \sqrt{7}$

---------------------------------------------------
Answer : x = 0 or 2√7 or -2√7
---------------------------------------------------

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3 years ago

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ANEK [815]

Answer:

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3 years ago

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kherson [118]

Since there are 12 months in there year and there have already been 3 months there are 9 left

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I hope I've helped!

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3 years ago

This is the third time i have asked this can someone please just give me the right answers please

Paha777 [63]

Answer:

3.since two base side are equal

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Step-by-step explanation:

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kherson [118]

The answer is j.
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