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3 years ago

Which statement describes an important role of carbon dioxide in Earth’s atmosphere? *

Chemistry

2 answers:

Leokris [45]3 years ago

8 0

Answer:

Plants use carbon dioxide to make food.

Explanation:

maw [93]3 years ago

7 0

Answer:B

Explanation: i did it

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Black hair (B) is dominant to brown hair (b). Cross a black rabbit and a brown hair. The black rabbit had a brown haired mother.

Fofino [41]

Answer:

Genotypic ratio = 1 Bb: 1 bb

Phenotypic ratio = 1 black rabbit : 1 brown rabbit

Explanation:

This question involves a gene coding for hair color in rabbits. The allele for Black hair (B) is dominant to the allele for brown hair (b).

According to this question, a black rabbit whose mother is brown haired (bb) is crossed with a brown hair rabbit. This means that the black rabbit will have a genotype 'Bb' while the brown rabbit will have a genotype 'bb'. Each parent will produce the following gametes:

Bb - B and b

bb - b and b

Using these gametes in a punnet square (see attached image), the following proportion of offsprings will be produced:

Bb, Bb, bb and bb

This means that the;

Genotypic ratio = 1 Bb: 1 bb

Phenotypic ratio = 1 black rabbit : 1 brown rabbit

7 0

3 years ago

Calculate the mass of oxygen per gram of sulfur for sulfur dioxide.

son4ous [18]

Sulfur dioxide has a molecular formula of SO2. The balanced chemical reaction leading to this isas shown below:

S + O2 ---> SO2

Therefore this means that 1 mole of sulfur and 1 mole of O2 reacts to form 1 mol of sulfur dioxide.

Assuming 1 mol of O2 and 1 mol of S for the sake of calculation, therefore:

mass oxygen, O = (1 mol O2) (2 mol O/ 1 mol O2) (16 g O/ mol O) = 32 g O

mass sulfur, S = 1 mol (32 g / mol) = 32 g

Therefore the ratio of O to S is:

O:S = 32 g O / 32 g S = 1 g O2/ 1 g S

Hence, there is 1 g of oxygen per 1 g of sulfur in sulfur dioxide.

3 0

4 years ago

What happens to the particles when heat is removed

BaLLatris [955]

I think the particle starts to move slowly around because no heat or pressure is applied to it

6 0

4 years ago

Read 2 more answers

Ammonium perchlorate is the solid rocket fuel used by the U.S. Space Shuttle. It reacts with itself to produce nitrogen gas , ch

FinnZ [79.3K]

Answer:

2.9 g of water are produced by 9.6 g of ammonium perchlorate

Note: The question is incomplete. The complete question is given below:

Ammonium perchlorate (NH₄ClO₄) is the solid rocket fuel used by the U.S. Space Shuttle. It reacts with itself to produce nitrogen gas (N₂) , chlorine gas (Cl₂), oxygen gas (O₂), water (H₂O) , and a great deal of energy. What mass of water is produced by the reaction of 9.6 g of ammonium perchlorate? Be sure your answer has the correct number of significant digits.

Explanation:

The reaction of ammonium perchlorate (NH₄ClO₄) to produce nitrogen gas (N₂) , chlorine gas (Cl₂), oxygen gas (O₂), water (H₂O) is shown in the balanced chemical equation given below:

2 NH₄ClO₄ → N₂ + Cl₂ + 2 O₂ + 4 H₂O

From the equation, 2 moles of ammonium perchlorate produces 4 moles of water, i.e. mole ratio of NH₄ClO₄ to H₂O = 2 : 4 = 1 : 2

molar mass of ammonium perchlorate, NH₄ClO₄ = (14 + 4 * 1 + 35.5 +16 * 4) = 117.5

molar mass of water, H₂O = (2 * 1 + 16) = 18.0 g

mass of water produced = moles of ammonium perchlorate * 2 * molar mass of water

moles of perchlorate = mass / molar mass = 9.6/117.5

mass of water produced = 9.6/117.5 * 2 * 18.0 g = 2.94 g of water

Therefore, 2.9 g of water are produced by 9.6 g of ammonium perchlorate

6 0

3 years ago

A chemist prepares a solution of silver(I) perchlorate by measuring out of silver(I) perchlorate into a volumetric flask and fil

3241004551 [841]

The question is incomplete, the complete question is;

A chemist prepares a solution of silver (I) perchlorate (AgCIO4) by measuring out 134.g of silver (I) perchlorate into a 50.ml volumetric flask and filling the flask to the mark with water. calculate the concentration in mol/L of the silver (I) perchlorate solution. Round your answer to 2 significant digits.

Answer:

13 mol/L

Explanation:

We must first obtain the number of moles of silver I perchlorate involved

Molar mass of silver I perchlorate = 207.32 g/mol

Number of moles of silver I perchlorate = 134g/207.32 g/mol = 0.646 moles

Recall that;

n =CV

C= concentration

V= volume

n = number of moles

C = n/V

C = 0.646 moles * 1000/50

C = 13 mol/L

8 0

3 years ago