C,
takes dead things, makes them into other things
The final volume of the methane gas in the container is 6.67 L.
The given parameters;
- <em>initial volume of gas in the container, V₁ = 2.65 L</em>
- <em>initial number of moles of gas, n₁ = 0.12 mol</em>
- <em>additional concentration, n = 0.182 mol</em>
The total number of moles of gas in the container is calculated as follows;

The final volume of gas in the container is calculated as follows;

Thus, the final volume of the methane gas in the container is 6.67 L.
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Answer:
MgCl2 + 2AgNO3 → 2AgCl + Mg(NO3)2
Explanation:
I'm assuming you want to balance it so...
The first thing I see is that there are two chlorines on the reactant side and one on the product side
Adding a coefficient of 2 would get 2AgCl2
Now there are two silvers on the reactant side, so add a 2 to AgNO3 on the products side. Now they are all balanced.
If that is not what you are looking for let me know!
Answer:
Zn(OH)2 + 2CH3COOH -----> Zn(CH3COO)2 + 2H2O
Explanation:
Zn(OH)2 + 2CH3COOH -----> Zn(CH3COO)2 + 2H2O