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balu736 [363]
4 years ago
8

Consider these elements: p, ca, si, s, ga. a. write the electron configuration for each element

Chemistry
1 answer:
dimulka [17.4K]4 years ago
7 0
Method:

1) Find the atomic number in a periodic table: the number of electrons equal the atomic number

2) Use Aufbau rule

Element     atomic number       electron configuration
<span>
P                15                            1s2 2s2 2p6 3s2 3p3

Ca              20                            </span><span><span>1s2 2s2 2p6 3s2 3p6 4s2

</span>Si                14</span><span>                            1s2 2s2 2p6 3s2 3p2

S                 16</span><span><span>                            1s2 2s2 2p6 3s2 3p4

</span>Ga               31.                   </span><span><span>        1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p</span>       </span>
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Ivahew [28]

Answer:

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6 0
3 years ago
It takes 53.0 J to raise the temperature of an 11.0 g piece of unknown metal from 13.0∘C to 24.2 ∘
jasenka [17]
You need to use q = mc(delta t) 
<span>Solve for c: </span>

<span>c = q / m(delta t) </span>

<span>q = 55.o J </span>
<span>m = 11.0 g </span>
<span>delta t = 24.5 - 13.0 = 11.5 deg C </span>

<span>c = 55 J / 11.0 g)(11.5 C) </span>
<span>c = 0.435 J/ g C</span>
7 0
3 years ago
An analysis reveals that a substance consists of 26.7% of carbon, 2.24% of hydrogen and 71.1% of oxygen, If the molar mass of th
exis [7]
 the   molecular  formula    is  calculated  as  follows 
find  the  mole  of  each  molecule 
that  is   for  carbon = 26.7/12=  2.23  moles
                   hydrogen=  2.24/1=2.24  moles
                 oxygen=  71.1/16=4.44  moles
find  the   mole  ratio  of  each  element
that  is  divide  all  moles  by  the  smallest  mole(  2.23)

for  carbon=2.23/2.23=1,
  hydrogen =  2.24/2,23=1
  oxygen= 4.44/2.23=  2
the   empirical  formula  = CHO2
therefore  the  molecular  formula=(CHO2)n=270.1
                 { ( 12x 1)  + 1x1) +(16x2)}n=270.1
45n=270.1 
n=6
molecular  formula  is  therefore=(CHO2)6=C6H6O12

7 0
3 years ago
A 0.479 g sample of nitrogen, oxygen or neon gas occupies a volume of 265 ml at 157 kpa and 20◦c. what is the molar mass and ide
Anna11 [10]
PV = nRT
P = 157 kPa = 157 × 10³ Pa
V = 265 ml = 0.265 l
T = 20°C = 293 K
m = 0.479 g
PV•M = mRT
M = (mRT)/(PV)
M = 0.479 g × 8.314 kPa.l/(mol.K) × 293 K / (157 kPa × 0.265 l)
M ≈ 28.04579 g/mol.
Hence, the Molar Mass of Dinitrogen or Nitrogen Gas is 28 g.
7 0
3 years ago
How many formula units of iron(III) oxide can be produced from the reaction of 108 g of iron with 72.1 L of oxygen gas at STP?
Irina-Kira [14]

Answer:

5.81 x 10^23 formula units Fe2O3

Explanation:

5 0
3 years ago
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