Answer:
V₂ = 16.5 L
Explanation:
To solve this problem we use <em>Avogadro's law, </em>which applies when temperature and pressure remain constant:
V₁/n₁ = V₂/n₂
In this case, V₁ is 22.0 L, n₁ is [mol CO + mol NO], V₂ is our unknown, and n₂ is [mol CO₂ + mol N₂].
- n₁ = mol CO + mol NO = 0.1900 + 0.1900 = 0.3800 mol
<em>We use the reaction to calculate n₂</em>:
2CO(g) + 2NO(g) → 2CO₂(g) + N₂(g)
0.1900 mol CO *
0.1900 mol CO₂
0.1900 mol NO *
0.095 mol N₂
- n₂ = mol CO₂ + mol N₂ = 0.1900 + 0.095 = 0.2850 mol
Calculating V₂:
22.0 L / 0.3800 mol = V₂ / 0.2850 mol
V₂ = 16.5 L
that is false it shows you the atoms but the arrangement would have to be a Lewis dot diagram
The temperature in K is 767.4 K
<u><em> calculation</em></u>
This is calculated using the ideal gas equation
that is PV =nRT
where;
P(pressure)= 28 atm
V(volume) = 0.045 L
n(number of moles)= 0.020 moles
R( gas constant) =0.0821 L.atm/mol.K
T(temperature)= ? K\
make T the subject of the formula by diving both side of equation by nR
T =PV/nR
T ={ (28 atm x 0.045 L) /( 0.020 mol x 0.0821 L.atm/mol.K)} =767.4 K