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3 years ago

Na +H₂O- NaOH +H₂ balance

Chemistry

1 answer:

Whitepunk [10]3 years ago

7 0

Hey there!

Na + H₂O → NaOH + H₂

First, balance O.

One on the left, one on the right. Already balanced.

Next, balance H.

Two on the left, three on the right. Let's add a coefficient of 2 in front of NaOH and a coefficient of 2 in front of H₂O, so we have 4 on each side.

Na + 2H₂O → 2NaOH + H₂

Lastly, balance Na.

One on the left, two on the right. Add a coefficient of 2 in front of Na.

2Na + 2H₂O → 2NaOH + H₂

This is our final balanced equation.

Hope this helps!

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Answer:

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4 years ago

A 255 mL round--bonom flask is weighed and found to have a mass of 114.85 g. A few millimeters of an easily vaporized liquid are

Alex17521 [72]

Answer: Option (d) is the correct answer.

Explanation:

According to the given situation, mass of compound will be calculated as follows.

Mass of compound = mass of flask and condensed vapor - mass of flask

= 115.23 - 114.85

= 0.38 g

Volume (V) = 255 mL = $255 \times 10^{-6} m^{3}$ (as 1 ml = $10^{-6} m^{3}$ )

Pressure (P) = 101325 Pa

Temperature = $100^{o}C$ = (100 + 273) K = 373 K

Now, according to the ideal gas equation, PV = nRT

and, moles of compound n = $\frac{PV}{RT}$

= $\frac{101325 \times 255 \times 10^{-6}}{8.314 \times 373}$

= 0.008332 mol

As, molar mass of compound = $\frac{mass}{\text{no. of moles}}$

= $\frac{0.38}{0.008332}$

= 46 g/mol

Therefore, the compound is $C_{2}H_{5}OH$ (molar mass = 12 x 2 + 5 x 1 + 16 + 1 = 46 g/mol).

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3 years ago

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A Glass pipet

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It is designed for measuring small units of volume accurately.
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When released, the liquid fills the tube.
The suction can be pressed at regular intervals to release the liquid till the desired volume is attained.

learn more:

Volume brainly.com/question/10691070

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3 years ago

How many Faradays of electricity are carried by 1.505×10^23 electronsk

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Mole of electron required by $1.505 *10^{23}$ mole is $2.5* 10 ^{-1}$

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There is one mole of electron required for 1 Faraday of electricity.

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Mole of electron can be calculated by dividing the number of electron by avogadro's constant.

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2 years ago