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erastovalidia [21]
3 years ago
10

All known frequencies of the visible spectrum are..

Physics
1 answer:
crimeas [40]3 years ago
7 0

Explanation:

b.  \: light

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A toy car is moving across a table with a velocity of 7.0 m/s and drives off the end. The table is 1.8 m tall. How long will the
KatRina [158]

Answer:

Option D - 0.2 s

Explanation:

We are given;

Initial velocity; u = 7 m/s

Height of table; h = 1.8m

Now,since we want to find the time the car spent in the air, we will simply use one of Newton's equation of motion.

Thus;

h = ut + ½gt²

Plugging in the relevant values, we have;

1.8 = 7t + ½(9.8)t²

4.9t² + 7t - 1.8 = 0

Using quadratic formula to find the roots of the equation gives us;

t = -1.65 or 0.22

We can't have negative t value, thus we will pick the positive one.

So, t = 0.22 s

This is approximately 0.2 s

7 0
4 years ago
Which of the following statements correctly compares ultraviolet and visible light?
Mazyrski [523]
I believe that the answer to this question is the letter A!
4 0
4 years ago
Which object is not accelerating?
AleksAgata [21]
I would say d because the student isn’t moving, the Ferris wheel is.
8 0
3 years ago
Read 2 more answers
Name the regions of a electromagnetic spectrum from the shortest wavelength to the longest wavelength
kaheart [24]

Answer:

From shortest wavelength to longest wavelength:

Gamma Rays

X-Rays

Ultraviolet

Visible Light

Infrared waves

Microwaves

Radio Waves

Explanation:

5 0
3 years ago
The spectrum from a hydrogen vapour lamp is measured and four lines in the visible light range are observed. These lines are the
Elan Coil [88]

Answer:

10942249.24 m^{-1}

Explanation:

Rydberg's formula is used to describe the wavelengths of the spectral lines of chemical elements similar to hydrogen, that is, with only one electron being affected by the effective nuclear charge. In this formula we can find the rydberg constant, knowing the wavelength emitted in the transcision between two energy states, we can have a value of the constant.

\frac{1}{\lambda}=Z^2R(\frac{1}{n^2_{1}}-\frac{1}{n^_{2}^2}})

Where \lambda it is the wavelength of the light emitted, R is the Rydberg constant, Z is the atomic number  of the element and n_{1} n_{2} are the states where n_{1}.

In this case we have Z=1 for hydrogen, solving for R:

R=\frac{1}{\lambda}*(\frac{1}{n^2_{1}}-\frac{1}{n^_{2}^2}})^{-1}\\R=\frac{1}{658.9*10^{-9}m}*(\frac{1}{2^2}-\frac{1}{3^2}})^{-1}\\R=1.52*10^6m^{-1}*(\frac{36}{5})=1.09*10^7 m^{-1}=10942249.24m^{-1}

This value is quite close to the theoretical value of the constant R=10967758.34 m^{-1}

5 0
3 years ago
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