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MatroZZZ [7]
3 years ago
9

Two students go to play basketball. They notice the ball is flat (it won't bounce). They decide to pump it up with air. After it

is pumped with air, will the ball have more, less, or the same amount of mass as before air was added?
A. The ball has less mass after being pumped with air.

B.Cannot determine unless we measure the mass.

C.The ball has more mass after being pumped with air.

D. The ball has the same amount of mass after being pumped with air.

Justify your answer
Physics
1 answer:
Wewaii [24]3 years ago
5 0
Answer: c. the ball has more mass after being pumped with air

explanation: the reason this is, is because air is made up of tiny particles that have mass. therefore, when more air is pumped into the basketball, the mass increases.
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inna [77]

Answer:

C

Explanation:

Hypothesis is one of the science methods. Hypothesis is the same as guessing. It's a scientific method that precedes observations.

According to the question asking that Which of the following is a hypothesis ?

The correct option is C which is

If a squid is attacked by a predator, it will squirt ink

It is an hypothesis because there is no experimental evidence to back it up.

5 0
3 years ago
ball of mass 0.4 kg is attached to the end of a light stringand whirled in a vertical circle of radius R = 2.9 m abouta fixed po
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Answer:

6.046N

Explanation:

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F_n_e_t=F_g+F_t

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F_n_e_t=ma_c=mv^2/r\\

where r is the rope's radius from the fixed point.

From the net force equation above:

F_t=F_n_e_t-F_g\\=mv^2/r-mg\\=0.4\times(8.5^2/2.9)-0.4\times9.8\\=6.046N

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8 0
3 years ago
A rock is dropped off a cliff and falls the first half of the distance to the ground in 2.0 seconds. how long will it take to fa
son4ous [18]

Answer:

The answer is 0.83 seconds.

Explanation:

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h=1/2*g*t^2

Where g=9.8 m/s^2 and t=2 seconds, the rock takes:

h=1/2*9.8*2^2=19.6

19.6 meters. This is the half distance of the cliff. The whole distance is 39.2 meters. So it takes:

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2.83 second to fall down completely. The rock takes the second half of the cliff in 0.83 seconds

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If 10. joules of work must be done to move 2.0 coulombs of charge from point A to point B in an electric field, the potential di
masya89 [10]
The equation for work (W) done by an electric field is:

W = qΔV

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10 = 2ΔV
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