There are two ways to solve this problem. First we write the given.
Given: Force F = 400 N; Height h = 0.5 m; Time t = 2 s
Formula: P = W/t; but Work W = Force x distance or W = f x d
Weight is also a Force, therefore: W = mg, solve for Mass m = ?
m = w/g m = 400 N/9.8 m/s² m = 40.82 Kg
P = W/t = F x d/t = mgh/t P = (40.82 Kg)(9.8 m/s²)/2 s
P = 100 J/s or 100 Watts
As we know that it has all given data given as


distance moved = 0.250 km = 250 m
now we can use kinematics to find acceleration



so it will accelerate at rate of 0.86 m/s^2
At a divergent boundary, plates move away from each other, allowing magma to fill up the cracks in between the plates to form new land. This creates rift valleys and mid ocean ridges.
Answer:
Explanation:
masie m = 20g = 20/1000 = 0.02kg
prędkość v = 50m/s
P.E = K.E = ½mv²
P.E = ½ × 0.02 × 50²
P.E = 25 J
pracę wykonana = P.E = 25J
<h2>Correct answer:</h2>

<h2>Explanation:</h2>
We can use voltage divider to solve this problem that is defined as the passive linear circuit producing an output voltage
that is a fraction of its input voltage
. So we can use the formula:
