M(NaOH)=15 g
v=600 ml=0.6 l
n(NaOH)=m(NaOH)/M(NaOH)
C=n(NaOH)/v=m(NaOH)/[M(NaOH)v]
C=15g/[40g/mol*0.6 l]=0.625 mol/l
0.625M
[H⁺]=7.5*10⁻²
pOH=14-pH=14+lg[H⁺]
pOH=14+lg(7.5*10⁻²)=14-1.125=12.875
Answer:
Explanation:
To solve this problem, we have to remember the ideal gas theory. We going to use the Gay Lussac Law.
The equation is:
PiTo = PoTi
Where:
<em>Pi =initial pressure</em>
<em>Po = final pressure</em>
<em>Ti = initial temperature</em>
<em>To = final temperature</em>
Let's use this equation and replace the values:
<em>Pi = 107 kPa</em>
<em>Ti = 22°C</em>
<em>To = 45 °C </em>
<em>Po = ? </em>
<em />
You can use the units as the problem gave you.
Using the Gay Lussac law:
107 kPa x 45 °C = Po x 22°C
Po = (4,815 kPa°C / 22°C) = 218.86 kPa
Po = 218 kPa
okie dokie I'll check it out right away
Answer:
Gas
Explanation:
Legend primordial element element by radioactive decay Atomic number color: red=gas
Answer:
Here you go I hope it helped you! :) good luck!
