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victus00 [196]
3 years ago
5

A circle has a radius of 5 feet and a central angle AOB that measures 10°. What is the length of the intercepted arc AB? Use 3.1

4 for pi and round your answer to the nearest tenth.
Chemistry
1 answer:
algol [13]3 years ago
5 0
We are asked to solve for the arc length of the intercepted arc and the formula is shown below:
Arc length = 2*pi*r(central angle/360°)
r = 5 feet
central angle = 10°

Solving for the arc length, we have:
Arc length = 2*3.14*5 (10/360)
Arc length = 0.872 feet

The arc length is 0.872 feet.
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Phosphine, an extremely poisonous and highly reactive gas, will react with oxygen to form tetraphosphorus decoxide and water, as
erica [24]

<u>Answer:</u> The amount of P_4O_{10} formed is 469.8 grams.

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}     ......(1)

Given mass of phosphine = 225 g

Molar mass of phosphine = 34 g/mol

Putting values in equation 1, we get:

\text{Moles of phosphine}=\frac{225g}{34g/mol}=6.62mol

The given chemical reaction follows:

4PH_3(g)+8O_2(g)\rightarrow P_4O_{10}(s)+6H_2O(g)

Assuming that oxygen gas is present in excess, it is considered as an excess reagent.

Phosphine is considered as a limiting reagent because it limits the formation of product.

By Stoichiometry of the reaction:

4 moles of phosphine produces 1 mole of P_4O_{10}

So, 6.62 moles of phosphine will produce = \frac{1}{4}\times 6.62=1.655mol of P_4O_{10}

Now, calculating the mass of P_4O_{10} by using equation 1:

Molar mass of P_4O_{10} = 283.9 g/mol

Moles of P_4O_{10} = 1.655 moles

Putting values in equation 1, we get:

1.655mol=\frac{\text{Mass of }P_4O_{10}}{283.9g/mol}\\\\\text{Mass of }P_4O_{10}=(1.655mol\times 283.9g/mol)=469.8g

Hence, the amount of P_4O_{10} formed is 469.8 grams.

8 0
3 years ago
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Answer:

crystalline and amorphous.

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Crystalline solids are the most common type of solid, they are characterized by a regular crystalline organization of atoms that confer a long-range order, Amorphous, or non-crystalline, solids lack the long-range order

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meriva
Notice that each reactant is made up of two elements. To predict the products, all you have to do is interchange the combination of the two reactants while taking note that metal comes first, followed by nonmetals. With that being said, the reaction would be:

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