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Alex787 [66]
3 years ago
14

C6H12O6 + 6O2 → 6CO2 + ? H2O + energy Whats the answer? I really don't know,

Chemistry
1 answer:
Ket [755]3 years ago
4 0

Answer:  C. 6

Explanation:

According to the Law of conservation of mass, mass can neither be created nor be destroyed. Thus the mass of products has to be equal to the mass of reactants. The number of atoms of each element has to be same on reactant and product side. Thus chemical equations are balanced.

The balanced chemical reaction for photosynthesis is :

C_6H_{12}O_6+6O_2\rightarrow 6CO_2+6H_2O+energy

Thus the coefficient of water is 6.

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B

Explanation:

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What is the with of the tank in cm that is0.20 meters
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I’m driving down the highway at 75.0 miles/hour, how fast is that in m/seconds?
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4 0
4 years ago
1.<br> Draw the Dot Structure for Na!
stepladder [879]

Answer:

Na ·

Explanation:

Hello!

In this case, since the Lewis dot structure of any element illustrates the number of valence electrons at the outer shell; we can set up the electron configuration of sodium to obtain:

Na^1^1\rightarrow 1s^2,2s^2,2p^6,3s^1

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Na ·

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3 years ago
Find the empirical formula of the following compounds:
Aneli [31]

The empirical formula of the following compounds 0.903 g of phosphorus combined with 6.99 g of bromine.

<h3>What is empirical formula?</h3>

The simplest whole number ratio of atoms in a compound is the empirical formula of a chemical compound in chemistry. Sulfur monoxide's empirical formula, SO, and disulfur dioxide's empirical formula, S2O2, are two straightforward examples of this idea. As a result, both the sulfur and oxygen compounds sulfur monoxide and disulfur dioxide have the same empirical formula.

<h3>How to find the empirical formula?</h3>

Convert the given masses of phosphorus and bromine into moles by multiplying the reciprocal of their molar masses. The molar masses of phosphorus and bromine are 30.97 and 79.90 g/mol, respectively.

Moles phosphorus = 0.903 g phosphorus \frac{mol phosphorus}{ 30.97 g phosphorus}= 0.0293 mol

Moles bromine 6.99 g bromine\frac{mol bromine}{79.90 g bromine}=0.0875 mol

The preliminary formula for compound is P0.0293Bro.0875. Divide all the subscripts by the subscript with the smallest value which is 0.0293. The empirical formula is P1.00Br2.99 ≈ P₁Br3 or PBr3

To learn more about empirical formula visit:

brainly.com/question/14044066

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8 0
1 year ago
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