Water boils at a temperature of _______ degrees on the celsius scale. a. 212 b. 194 c. 100 d. 90

A frictionless piston cylinder device is subjected to 1.013 bar external pressure. The piston mass is 200 kg, it has an area of

Bad White [126]

Answer:

a) $T_{2} = 360.955\,K$ , $P_{2} = 138569.171\,Pa\,(1.386\,bar)$ , b) $T_{2} = 347.348\,K$ , $V_{2} = 0.14\,m^{3}$

Explanation:

a) The ideal gas is experimenting an isocoric process and the following relationship is used:

$\frac{T_{1}}{P_{1}} = \frac{T_{2}}{P_{2}}$

Final temperature is cleared from this expression:

$Q = n\cdot \bar c_{v}\cdot (T_{2}-T_{1})$

$T_{2} = T_{1} + \frac{Q}{n\cdot \bar c_{v}}$

The number of moles of the ideal gas is:

$n = \frac{P_{1}\cdot V_{1}}{R_{u}\cdot T_{1}}$

$n = \frac{\left(101,325\,Pa + \frac{(200\,kg)\cdot (9.807\,\frac{m}{s^{2}} )}{0.15\,m^{2}} \right)\cdot (0.12\,m^{3})}{(8.314\,\frac{Pa\cdot m^{3}}{mol\cdot K} )\cdot (298\,K)}$

$n = 5.541\,mol$

The final temperature is:

$T_{2} = 298\,K +\frac{10,500\,J}{(5.541\,mol)\cdot (30.1\,\frac{J}{mol\cdot K} )}$

$T_{2} = 360.955\,K$

The final pressure is:

$P_{2} = \frac{T_{2}}{T_{1}}\cdot P_{1}$

$P_{2} = \frac{360.955\,K}{298\,K}\cdot \left(101,325\,Pa + \frac{(200\,kg)\cdot (9.807\,\frac{m}{s^{2}} )}{0.15\,m^{2}}\right)$

$P_{2} = 138569.171\,Pa\,(1.386\,bar)$

b) The ideal gas is experimenting an isobaric process and the following relationship is used:

$\frac{T_{1}}{V_{1}} = \frac{T_{2}}{V_{2}}$

Final temperature is cleared from this expression:

$Q = n\cdot \bar c_{p}\cdot (T_{2}-T_{1})$

$T_{2} = T_{1} + \frac{Q}{n\cdot \bar c_{p}}$

$T_{2} = 298\,K +\frac{10,500\,J}{(5.541\,mol)\cdot (38.4\,\frac{J}{mol\cdot K} )}$

$T_{2} = 347.348\,K$

The final volume is:

$V_{2} = \frac{T_{2}}{T_{1}}\cdot V_{1}$

$V_{2} = \frac{347.348\,K}{298\,K}\cdot (0.12\,m^{3})$

$V_{2} = 0.14\,m^{3}$

4 0

3 years ago

The rate constant for a particular zero-order reaction is 0.075 M s-1. If the initial concentration of reactant is 0.537 M it ta

Anarel [89]

Answer:

It takes 5.83s to decrease the concentration of the reactant from 0.537M to 0.100M

Explanation:

A zero-order reaction follows the equation:

[A] = [A]₀ - kt

<em>Where [A] is actual reaction of the reactant = 0.100M</em>

<em>[A]₀ the initial concentration = 0.537M</em>

<em>k is rate constant = 0.075Ms⁻¹</em>

<em>And t is time it takes:</em>

<em />

0.100M = 0.537M -0.075Ms⁻¹t

-0.437M = -0.075Ms⁻¹t

5.83s = t

It takes 5.83s to decrease the concentration of the reactant from 0.537M to 0.100M

8 0

3 years ago

Given the equation: HCI + Na2SO4 ---> NaCl + H2SO4 Hint: you should balance the equation If you start with 2.0 g of HCl (hydr

Rasek [7]

Answer:

approx 2.45g

Explanation:

2HCl + Na2SO4 → 2NaCl + H2SO4

2 : 1 : 2 : 1

0.05 0.025 (moles)

⇒ mH2SO4 = 0.025 × 98 = 2.45 g

3 0

2 years ago

What is the name of the planet next to the label A?

goldenfox [79]

Answer:

B. Neptune. Neptune is next to Uranus

8 0

2 years ago

How might this graph be different if the farmers had grown a wide variety of potato plants or had included other crops in their

mote1985 [20]

The graph would not have plummeted if various species were planted due to improvement of the potato crops.

<h3>What is variety?</h3>

The term variety has to do with the planting of different species of plants on the same farm. We know that the planting of different species of the same crop helps to improve the resistance to diseases of a plant.

Hence, the graph would not have plummeted if various species were planted due to improvement of the potato crops.

Learn more about improved specie:brainly.com/question/3627477

#SPJ1

3 0

1 year ago