Answer: <u>b</u><u>a</u><u>l</u><u>e</u><u> </u><u>2</u><u> </u><u>e</u><u>l</u><u>e</u><u>m</u><u>e</u><u>n</u><u>t</u><u>s</u><u> </u><u>s</u><u>y</u><u>a</u><u> </u><u>a</u><u>n</u><u>g</u><u> </u><u>m</u><u>g</u><u>a</u><u> </u><u>y</u><u>o</u><u>n</u><u> </u><u>a</u><u>y</u><u> </u><u>h</u><u>y</u><u>d</u><u>r</u><u>o</u><u>g</u><u>e</u><u>n</u><u> </u><u>a</u><u>t</u><u> </u><u>o</u><u>x</u><u>y</u><u>g</u><u>e</u><u>n</u><u>.</u>
H2O is a molecule made of H for hydrogen and O for oxygen. There are 12 of these molecules. The smaller number is the number of atoms of the element to the left of it.
<em>M</em><em>A</em><em>R</em><em>K</em><em> </em><em>M</em><em>E</em><em> </em><em>A</em><em>S</em><em> </em><em>A</em><em> </em><em>B</em><em>R</em><em>A</em><em>I</em><em>N</em><em>L</em><em>I</em><em>E</em><em>S</em><em>T</em><em> </em><em>P</em><em>L</em><em>E</em><em>A</em><em>S</em><em>E</em>
It is the symbol used to represent nano meters.
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Answer: The mass of 45.0 L of at 87.0° C and 750 mm Hg is 56.605 g.
Explanation:
Given: Volume = 45.0 L
Temperature = = (87.0 + 273) K = 360 K
Pressure = 750 mm Hg (1 mm Hg = 0.00131579 atm) = 0.98 atm
Formula used to calculate moles is as follows.
PV = nRT
where,
P = pressure
V = volume
n = no. of moles
R = gas constant = 0.0821 L atm/mol K
T = temperature
Substitute the values into above formula as follows.
Moles is the mass of a substance divided by its molar mass. So, mass of (molar mass = 37.99 g/mol) is calculated as follows.
Thus, we can conclude that the mass of 45.0 L of at 87.0° C and 750 mm Hg is 56.605 g.