<span>4 Al + 3 O2 → 2 Al2O3
(10.0 g Al) / (26.98154 g Al/mol) = 0.37062 mol Al
(19.0 g O2) / (31.99886 g O2/mol) = 0.59377 mol O2
0.37062 mole of Al would react completely with 0.37062 x (3/4) = 0.277965 mole of O2, but there is more O2 present than that, so O2 is in excess.
((0.59377 mol O2 initially) - (0.277965 mol O2 reacted)) x (31.99886 g O2/mol) =
10.1 g O2 left over</span><span>
</span>
Density is weight by volume.
First. If you divide the weight by density you can find the volume
Second you must convert the ML in to Liters.

1L=1000ml


0.38214 Liters.
a. An oxidation reaction. An oxidation reaction is a type of chemical reaction that involves a transfer of electrons between two species.
The Answer is 10 it a little difficult to explain but I’ll try my best