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LUCKY_DIMON [66]
3 years ago
6

Calculate the pHpH of a 0.10 MM solution of barium hydroxide, Ba(OH)2Ba(OH)2. Express your answer numerically using two decimal

places.
Chemistry
2 answers:
Temka [501]3 years ago
8 0

Answer:

The pH of this barium hydroxide solution is 13.30

Explanation:

Step 1: Data given

Concentration Ba(OH)2 = 0.10 M

Step 2: Calculate [OH-]

Ba(OH)2 ⇒ Ba^2+ + 2OH-

[OH-] = 2*0.10 M

[OH-] = 0.20 M

Step 3: Calculate pOH

pOH = -log[OH-]

pOH = -log(0.20)

pOH = 0.70

Step 4: Calculate pH

pH + pOH = 14

pH = 14 -pOH

pH = 14 - 0.70

pH = 13.30

The pH of this barium hydroxide solution is 13.30

Maurinko [17]3 years ago
6 0

Answer:

13.301

Explanation:

To calculate the pH of the solution, we must obtain the pOH of the solution as illustrated below:

The dissociation equation is given below

Ba(OH)2 <==> Ba^2+ + 2OH^-

Since Ba(OH)2 dissociate to produce 2moles of OH^-, the concentration of OH^- = 2x0.1 = 0.2M

pOH = - Log[OH^-]

pOH = - Log 0.2

pOH = 0.699

But

pH + pOH = 14

pH = 14 — pOH

pH = 14 — 0.699

pH = 13.301

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1 year ago
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What kind of reaction does Iron (III) and copper (II) sulfate solution produce?
ivanzaharov [21]

Answer:

The answer to your question is Single replacement

Explanation:

Types of reaction in Chemistry

Synthesis           two or more reactants combine to produce one single product

Decomposition      one reactant splits producing two or more products

Single replacement  One element replaces a similar one in a compound.

Double replacement Two compounds interchange their cations and anions.

Combustion one compound reacts with oxygen to produce carbon dioxide and water.

Reaction given

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This is a single replacement reaction

4 0
3 years ago
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What mass of oxygen (O2) forms in a reaction that forms 15.90 g C6H12O6? (Molar mass of O2 = 32.00 g/mol; molar mass of C6H12O6
Dafna11 [192]

The answer is: the mass of oxygen is 16.95 grams.

The overall balanced photosynthesis reaction:  

6CO₂ + 6H₂O → C₆H₁₂O₆ + 6O₂.  

m(C₆H₁₂O₆) = 15.90 g; mass of glucose.

n(C₆H₁₂O₆) = m(C₆H₁₂O₆) ÷ M(C₆H₁₂O₆).

n(C₆H₁₂O₆) = 15.9 g ÷ 180.18 g/mol.

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n(O₂) = 6 · 0.088 mol.

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m(O₂) = 0.53 mol · 32.00 g/mol.

m(O₂) = 16.95 g; mass of oxygen.

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3 years ago
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A gas has a volume of 1.75L at -23C and 150.0kPa. At what temperature would the gas occupy 1.30L at 210.0kPa?
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Answer:

T2 = 260 K  

Explanation:

<em>Given data:</em>

P1 = 150.0 k Pa

T1 = (-23+ 273.15) K = 250.15 K  

V1 = 1.75 L  

P2 = 210.0 kPa  

V2 = 1.30 L

<em>To find:</em>

T2 = ?

<em>Formula:</em>

\frac{P_1 V_1}{T_1} = \frac{P_2 V_2}{T_2}

T_2 = \frac{P_2 V_2 T_1}{P_1 V_1}

<em>Calculation:</em>

T2 = (210.0 kPa) x (1.30 L) x (250.15 K) / (150.0 kPa) x (1.75 L)

T2 = 260 K  

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9/4

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