The monochloroderivatives will be obtained by substituting chemically non equivalent hydrogen with chlorine atom, one by one
So the possible monochloro derivatives of 2,4-dimethylpentane (figure 1) are shown in figure (2)
Butane reacts with chlorine to form 2 isomers. Name these 2 isomers.
2 answers:
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Answer:
The formula of Estrone =
Explanation:
Mass of water obtained = 1.388 g
Molar mass of water = 18 g/mol
<u>Moles of = 1.388 g /18 g/mol = 0.07711 moles
</u>
2 moles of hydrogen atoms are present in 1 mole of water. So,
Moles of H = 2 x 0.07711 = 0.1542 moles
Molar mass of H atom = 1.008 g/mol
<u>Mass of H in molecule = 0.1542 x 1.008 = 0.1555 g </u>
Mass of carbon dioxide obtained = 5.543 g
Molar mass of carbon dioxide = 44.01 g/mol
Moles of = 5.543 g /44.01 g/mol = 0.126 moles
1 mole of carbon atoms are present in 1 mole of carbon dioxide. So,
<u>Moles of C = 0.126 moles </u>
Molar mass of C atom = 12.0107 g/mol
<u>Mass of C in molecule = 0.126 x 12.0107 = 1.5133 g </u>
Given that the Estrone only contains hydrogen, oxygen and carbon. So,
Mass of O in the sample = Total mass - Mass of C - Mass of H
Mass of the sample = 1.893 g
Mass of O in sample = 1.893 - 1.5133 - 0.1555 = 0.2242 g
Molar mass of O = 15.999 g/mol
<u>Moles of O = 0.2242 / 15.999 = 0.01401 moles </u>
Taking the simplest ratio for H, O and C as:
0.1542 : 0.01401 : 0.126
<u> = 11 :1 : 9</u>
<u>The empirical formula is =
</u>
Molecular formulas is the actual number of atoms of each element in the compound while empirical formulas is the simplest or reduced ratio of the elements in the compound.
Thus,
Molecular mass = n × Empirical mass
Where, n is any positive number from 1, 2, 3...
Mass from the Empirical formula = 9×12 + 11×1 + 16= 135 g/mol
Given, Molar mass = 270.36 g/mol
So,
Molecular mass = n × Empirical mass
270.36 = n × 135
<u>⇒ n = 2 </u>
<u>The formula of Estrone =
</u>