Answer:
0.6 moles of CaO will produced.
Explanation:
Given data:
Mass of calcium = 23.9 g
Moles of CaO produced = ?
Solution:
Chemical equation:
2Ca + O₂ → 2CaO
Number of moles of calcium:
Number of moles = mass/ molar mass
Number of moles = 23.9 g / 40 g/mol
Number of moles = 0.6 mol
Now we will compare the moles of calcium and CaO.
Ca : CaO
2 : 2
0.6 : 0.6
0.6 moles of CaO will produced.
Answer:
The least electronegative elements in the center of lewis structures because an atom in the central position shares more of its electrons than does a terminal atom. Atoms with higher electronegative are generally more reluctant to share their electrons.
Explanation:
Based on the data given, the molar mass of the gas is 165.5 g/mol while the molecular weight of the gas is 165.5 amu
<h3>How can molar mass of a gas be obtained from density, temperature and pressure?</h3>
The molar mass of a gas can be obtained from density, temperature and pressure using the formula below:
- molar mass = density × molar gas constant × temperature/pressure
Molar gas constant, R = R = 0.082 L.atm/mol/K.
Temperature = 150 °C = 423 K
Pressure = 785 torr = 1.033 atm
density = 4.93 g/L
molar mass of gas = 4.93 × 0.082 × 423/1.033
molar mass of gas = 165.5 g/mol
Then, molecular weight of the gas = 165.5 amu
Therefore, the molar mass of the gas is 165.5 g/mol while the molecular weight of the gas is 165.5 amu
Learn more about molar mass of a gas at: brainly.com/question/26215522
Answer:
<u>It increases by a factor of four</u>
Explanation:
Boyle's Law : At constant temperature , the volume of fixed mass of a gas is inversely proportional to its pressure.
pV = K.......(1)
pV = constant
Charles law : The volume of the gas is directly proportional to temperature at constant pressure.
V = KT
or V/T = K = constant ....(2)
Applying equation (1) and (2)


According to question ,
T2 = 4 (T1)
V2 = V1
Put the value of T2 and V2 , The P2 can be calculated,

V1 and V1 cancel each other
T1 and T1 cancel each other
We get,

or
P2 = 4 P1
So pressure increased by the factor of four