Given :
The average acceleration of a tennis ball that has an initial velocity of 6.0 m/s.
and a final velocity of 7.3 m/s.
It is in contact with a tennis racket for 0.094 s
To Find :
The average acceleration of the tennis ball.
Solution :
We know, average acceleration is given by :

Therefore, average velocity is given by 13.83 m/s².
Hence, this is the required solution.
Answer:

Explanation:
Here we know that for the given system of charge we have no loss of energy as there is no friction force on it
So we will have


now we know when particle will reach the closest distance then due to electrostatic repulsion the speed will become zero.
So we have



so distance moved by the particle is given as



Answer:
6.14 s
Explanation:
The time the rocket takes to reach the top is only determined from its vertical motion.
The initial vertical velocity of the rocket is:

where
u = 100 m/s is the initial speed
is the angle of launch
Now we can apply the suvat equation for an object in free-fall:

where
is the vertical velocity at time t
is the acceleration of gravity
The rocket reaches the top when

So by substituting into the equation, we find the time t at which this happens:

Answer:
Correct answer: The carpet material is soft, non-stick and diffuse and therefore absorbs waves.
Explanation:
The room is more acoustic if the walls and ceiling and floor are made of hard and polished material that reflects sound waves well while the carpeted room absorbs sound waves so it is less acoustic. The carpet material is soft, non-stick and diffuse and therefore absorbs waves.
God is with you!!!