3 years ago

How do I answer 15 and 16? Help please, I have a test tomorrow

Physics

1 answer:

eduard3 years ago

8 0

15) Use v^2=u^2+2as

So (65)^2=(0)^2+2(2.50)(s)

Then just solve that^.

You might be interested in

A solid metal sphere with radius 0.430 m carries a net charge of 0.270 nC . Part A Find the magnitude of the electric field at a

rodikova [14]

Answer:

8.46 N/C

Explanation:

Using Gauss law

$E=\frac {kQ}{r^{2}}$

Gauss's Law states that the electric flux through a surface is proportional to the net charge in the surface, and that the electric field E of a point charge Q at a distance r from the charge

Here, K is Coulomb's constant whose value is $9\times 10^{9} Nm^{2}/C^{2}$

r = 0.43 + 0.106 = 0.536 m

$E=\frac {9\times 10^{9}\times 0.270\times 10^{-9}}{0.536^{2}}=8.4581755402094007\approx 8.46 N/C$

8 0

4 years ago

“Active listening” means to _______________. a. be quiet when someone is speaking b. check your understanding of what someone sa

DIA [1.3K]

Answer:

All of the above is the correct answer!!!

Explanation:

mark me brainliest

4 0

2 years ago

A car traveling at 24 m/s starts to decelerate steadily. It comes to a complete stop in 8 seconds. What is its acceleration?

aleksklad [387]

Formula for velocity:
V(t) = Vi + at
Where V(t) is velocity at time t, Vi is initital velocity, and a is acceleration.
Solving for a:
V(8) = Vi + a(8)
V(8) = 0 (car has stopped)
0 = 24 + 8a
-24 = 8a
a = -3 m/s/s

6 0

3 years ago

Radiation is energy that is (5 points) not transferred at all transferred by direct contact of two objects transferred by moving

BARSIC [14]

There isn't a question here so, true

3 0

4 years ago

Please help !! In the diagram, q1 = +0.00200 C, q2 = 0.00180 C, and q3 = +0.00830 C. the net force on q2 is zero. how far is q2

VikaD [51]

Answer:

2.03715

Explanation:

$32364=8.99\cdot 10^9\cdot \frac{0.00180\cdot 0.00830}{2.03715^2}$

4 0

4 years ago