Ask question

Ask question

All categories

mihalych1998 [28]

2 years ago

14

An elevator is moving upward with a speed of 9.2 m/s. 3.8 seconds later, the elevator is still moving upward, but its speed has

increased to 15.8 m/s. What is the average acceleration, in m/s2, of the elevator during the 3.8-s interval? Please round your answer to one decimal place.

1 answer:

Zigmanuir [339]2 years ago

6 0

From the calculations, the acceleration of the elevator is obtained as 1.5m/s^2

<h3>What is acceleration?</h3>

The term acceleration has to do with the rate of change of velocity with time.

Given that;

u = 9.2 m/s

v = 15.8 m/s

t = 3.8

a = ?

The v = u + at

a = v - u/t

a = 15 - 9.2/3.8

a = 1.5m/s^2

Learn more about acceleration:brainly.com/question/12550364

#SPJ1

You might be interested in

What name is given to a generator which produce alternating current

defon

Answer:

alternator

Explanation:

AC - Altanator

DC - Dynamo

4 0

3 years ago

Calculate the ratio of the resistance of 12.0 m of aluminum wire 2.5 mm in diameter, to 30.0 m of copper wire 1.6 mm in diameter

alukav5142 [94]

Answer: 0.258

Explanation:

The resistance $R$ of a wire is calculated by the following formula:

$R=\rho\frac{l}{s}$ (1)

Where:

$\rho$ is the resistivity of the material the wire is made of. For aluminium is $\rho_{Al}=2.65(10)^{-8}m\Omega$ and for copper is $\rho_{Cu}=1.68(10)^{-8}m\Omega$

$l$ is the length of the wire, which in the case of aluminium is $l_{Al}=12m$ , and in the case of copper is $l_{Cu}=30m$

$s$ is the transversal area of the wire. In this case is a circumference for both wires, so we will use the formula of the area of the circumference:

$s=\pi{(\frac{d}{2})}^{2}$ (2) Where $d$ is the diameter of the circumference.

For aluminium wire the diameter is $d_{Al}=2.5mm=0.0025m$ and for copper is $d_{Cu}=1.6mm=0.0016m$

So, in this problem we have two transversal areas:

<u>For aluminium:</u>

$s_{Al}=\pi{(\frac{d_{AL}}{2})}^{2}=\pi{(\frac{0.0025m}{2})}^{2}$

$s_{Al}=0.000004908m^{2}$ (3)

<u>For copper:</u>

$s_{Cu}=\pi{\frac{(d_{Cu}}{2})}^{2}=\pi{(\frac{0.0016m}{2})}^{2}$

$s_{Cu}=0.00000201m^{2}$ (4)

Now we have to calculate the resistance for each wire:

<u>Aluminium wire:</u>

$R_{Al}=2.65(10)^{-8}m\Omega\frac{12m}{0.000004908m^{2}}$ (5)

$R_{Al}=0.0647\Omega$ (6) Resistance of aluminium wire

<u>Copper wire:</u>

$R_{Cu}=1.68(10)^{-8}m\Omega\frac{30m}{0.00000201m^{2}}$ (6)

$R_{Cu}=0.250\Omega$ (7) Resistance of copper wire

At this point we are able to calculate the ratio of the resistance of both wires:

$Ratio=\frac{R_{Al}}{R_{Cu}}$ (8)

$\frac{R_{Al}}{R_{Cu}}=\frac{0.0647\Omega}{0.250\Omega}$ (9)

Finally:

$\frac{R_{Al}}{R_{Cu}}=0.258$ This is the ratio

3 0

4 years ago

What advantage does a telescope in space have over one located on the ground.

klio [65]

A telescope in space can focus on any object while a telescope on the ground cannot focus on the object it is on

7 0

4 years ago

Why is magnetic force a non contact force?

lianna [129]

Bcoz when you place a magnet close enough the magnet attracts or repals without any other fore we dont touch the magnet so it is non contact

6 0

3 years ago

Derive an expression to show tha v=✓2Gr

Elza [17]

Answer:

From this equation, it can be said that the escape velocity depends on the radius of the planet and the mass of the planet only and not on the mass of the body. Escape Velocity of Earth= 11.2 km/s. This was the derivation of the escape velocity of earth or any other planet.

Explanation:

8 0

2 years ago