Answer:
Explanation:
Henry's law states that the solubility of a gas is directly proportional to its partial pressure. The equation may be written as:
Where 
is Henry's law constant.
Our strategy will be to identify the Henry's law constant for oxygen given the initial conditions and then use it to find the solubility at different conditions.
Given initially:
Also, at sea level, we have an atmospheric pressure of:
Given mole fraction:
According to Dalton's law of partial pressures, the partial pressure of oxygen is equal to the product of its mole fraction and the total pressure:
Then the equation becomes:
Solve for :
Now we're given that at an altitude of 12,000 ft, the atmospheric pressure is now:
Apply Henry's law using the constant we found:
Answer: Explanation: Speed is simply velocity without a specified direction (speed is the magnitude of the velocity vector). Regardless of the two measurements, they both relate distance to time, but are slightly different. Instantaneous speed is the derivative of the total distance covered with respect to time.
Explanation: I hope this helps!
Answer:
36.55kJ/mol
Explanation:
The heat of solution is the change in heat when the KNO3 dissolves in water:
KNO3(aq) → K+(aq) + NO3-(aq)
As the temperature decreases, the reaction is endothermic and the molar heat of solution is positive.
To solve the molar heat we need to find the moles of KNO3 dissolved and the change in heat as follows:
<em>Moles KNO3 -Molar mass: 101.1032g/mol-</em>
10.6g * (1mol/101.1032g) = 0.1048 moles KNO3
<em>Change in heat:</em>
q = m*S*ΔT
<em>Where q is heat in J,</em>
<em>m is the mass of the solution: 10.6g + 251.0g = 261.6g</em>
S is specififc heat of solution: 4.184J/g°C -Assuming is the same than pure water-
And ΔT is change in temperature: 25°C - 21.5°C = 3.5°C
q = 261.6g*4.184J/g°C*3.5°C
q = 3830.87J
<em>Molar heat of solution:</em>
3830.87J/0.1048 moles KNO3 =
36554J/mol =
<h3>36.55kJ/mol</h3>
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